Java BigDecimal 删除小数和尾随数字
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/1316945/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Java BigDecimal remove decimal and trailing numbers
提问by Zero Cool
I'm new to Java and trying to take a BigDecimal (for example 99999999.99) and convert it to a string but without the decimal place and trailing numbers. Also, I don't want commas in the number and rounding is not needed.
我是 Java 新手，并尝试使用 BigDecimal（例如 99999999.99）并将其转换为字符串，但没有小数位和尾随数字。另外，我不想在数字中使用逗号，也不需要四舍五入。
I've tried:
我试过了：
Math.Truncate(number)
but BigDecimal is not supported.
但不支持 BigDecimal。
Any ideas?
有任何想法吗？
Thanks very much.
非常感谢。
采纳答案by David Z
Try number.toBigInteger().toString()
尝试 number.toBigInteger().toString()
回答by S.Lott
Use this.
用这个。
BigDecimal truncated= number.setScale(0,BigDecimal.ROUND_DOWN);
回答by ZZ Coder
BigDecimal without fractions is BigInteger. Why don't you just use BigInteger?
没有分数的 BigDecimal 是 BigInteger。为什么不直接使用 BigInteger？
回答by Vinayak Patil
private void showDoubleNo(double n) {
double num = n;
int decimalPlace = 2;
BigDecimal bd = new BigDecimal(num);
bd = bd.setScale(decimalPlace,BigDecimal.ROUND_UP);
System.out.println("Point is "+bd);
}
回答by Flavio H. Furlanetto
Here's the most elegant way I found to resolve this:
这是我找到的最优雅的解决方法：
public static String convertDecimalToString (BigDecimal num){
String ret = null;
try {
ret = num.toBigIntegerExact().toString();
} catch (ArithmeticException e){
num = num.setScale(2,BigDecimal.ROUND_UP);
ret = num.toPlainString();
}
return ret;
}
回答by puneetShanbhag
public static String convertBigDecimalToString(BigDecimal bg) {
System.out.println("Big Decimal Value before its convertion :" + bg.setScale(2, BigDecimal.ROUND_HALF_UP));
String bigDecStringValue = bg.setScale(0,BigDecimal.ROUND_HALF_UP).toPlainString();
System.out.println("Big Decimal String Value after removing Decimal places is :" + bigDecStringValue);
return bigDecStringValue;
}
Please note : I have used 'BigDecimal.ROUND_HALF_UP' , just to make sure, Rounding mode to round towards "nearest neighbor" unless both neighbors are equidistant
请注意：我使用了 'BigDecimal.ROUND_HALF_UP' ，只是为了确保舍入模式向“最近的邻居”舍入，除非两个邻居等距
