Linux 如何在匹配/匹配后使用“sed”删除 2 行？
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How can I use "sed" to delete 2 lines after match/matches?
提问by wael
I have the following command : sed -i -e '/match1/,+2d' filex, which deletes 2 lines after finding the match "match1" in the file "file x". I want to add several matches to it, like match1, match 2 ....
我有以下命令 : sed -i -e '/match1/,+2d' filex，它在文件“文件 x”中找到匹配项“match1”后删除 2 行。我想向它添加几个匹配项，例如 match1、match 2 ....
So it will delete 2 lines after finding any of the matches, how can I achieve this ?
因此，它会在找到任何匹配项后删除 2 行，我该如何实现？
回答by ziu
Two ways, depending upon the sed version and platform:
两种方式，取决于 sed 版本和平台：
sed -e '/match1/,+2d' -e '/match2/,+2d' < oldfile > newfile
or
或者
sed -e '/match1\|match2/,+2d' < oldfile > newfile
回答by Max
Not a sed user but it seems to me you could use :
不是 sed 用户，但在我看来您可以使用：
sed -i -e '/(match1|match2)/,+2d' filex
Otherwise you could, if that's possible for you to do, do :
否则，如果您可以这样做，您可以这样做：
sed -i -e '/match1/,+2d' filex && sed -i -e '/match2/,+2d' filex
EDIT: Looks like I had the right idea but ziu got it.
编辑：看起来我的想法是正确的，但 ziu 明白了。
回答by sehe
If I understand you correctly, you want
如果我理解正确，你想要
sed -e '/match1/,+2d' input.txt
For example, create input with seq 10 | sed '3i match1' > input.txt:
例如，使用以下命令创建输入seq 10 | sed '3i match1' > input.txt：
1
2
match1
3
4
5
6
7
8
9
10
The output of sed -e '/match1/,+2d' input.txtwould be:
的输出sed -e '/match1/,+2d' input.txt将是：
1
2
5
6
7
8
9
10
