Python iMAP 电子邮件访问的正确格式示例？
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Properly formatted example for Python iMAP email access?
提问by Brian C. Lane
tldr: Can someone show me how to properly format this Python iMAP example so it works?
tldr：有人可以告诉我如何正确格式化这个 Python iMAP 示例以使其有效吗？
from https://docs.python.org/2.4/lib/imap4-example.html
来自 https://docs.python.org/2.4/lib/imap4-example.html
import getpass, imaplib M = imaplib.IMAP4() M.login(getpass.getuser(), getpass.getpass()) M.select() typ, data = M.search(None, 'ALL') for num in data[0].split(): typ, data = M.fetch(num, '(RFC822)') print 'Message %s\n%s\n' % (num, data[0][1]) M.close() M.logout()
import getpass, imaplib M = imaplib.IMAP4() M.login(getpass.getuser(), getpass.getpass()) M.select() typ, data = M.search(None, 'ALL') for num in data[0].split(): typ, data = M.fetch(num, '(RFC822)') print 'Message %s\n%s\n' % (num, data[0][1]) M.close() M.logout()
Assuming my email is "[email protected]" and the password is "password," how should this look? I tried M.login(getpass.getuser([email protected]), getpass.getpass(password))and it timed out. Complete newb here, so it's very likely I missed something obvious (like creating an iMAP object first? Not sure).
假设我的电子邮件是“[email protected]”，密码是“password”，这看起来如何？我试过了M.login(getpass.getuser([email protected]), getpass.getpass(password))，超时了。在这里完成新手，所以很可能我错过了一些明显的东西（比如先创建一个 iMAP 对象？不确定）。
回答by tzot
import imaplib
# you want to connect to a server; specify which server
server= imaplib.IMAP4_SSL('imap.googlemail.com')
# after connecting, tell the server who you are
server.login('[email protected]', 'password')
# this will show you a list of available folders
# possibly your Inbox is called INBOX, but check the list of mailboxes
code, mailboxen= server.list()
print mailboxen
# if it's called INBOX, then…
server.select("INBOX")
The rest of your code seems correct.
您的其余代码似乎是正确的。
回答by Brian C. Lane
Here is a script I used to use to grab logwatch info from my mailbox. Presented at LFNW 2008-
这是我用来从我的邮箱中获取 logwatch 信息的脚本。在 LFNW 2008 上发表-
#!/usr/bin/env python
''' Utility to scan my mailbox for new mesages from Logwatch on systems and then
grab useful info from the message and output a summary page.
by Brian C. Lane <[email protected]>
'''
import os, sys, imaplib, rfc822, re, StringIO
server ='mail.brianlane.com'
username='yourusername'
password='yourpassword'
M = imaplib.IMAP4_SSL(server)
M.login(username, password)
M.select()
typ, data = M.search(None, '(UNSEEN SUBJECT "Logwatch")')
for num in data[0].split():
typ, data = M.fetch(num, '(RFC822)')
# print 'Message %s\n%s\n' % (num, data[0][1])
match = re.search( "^(Users logging in.*?)^\w",
data[0][1],
re.MULTILINE|re.DOTALL )
if match:
file = StringIO.StringIO(data[0][1])
message = rfc822.Message(file)
print message['from']
print match.group(1).strip()
print '----'
M.close()
M.logout()
回答by ayaz
Did you forget to specify the IMAP host and port? Use something to the effect of:
您是否忘记指定 IMAP 主机和端口？使用一些东西来达到以下效果：
M = imaplib.IMAP4_SSL( 'imap.gmail.com' )
or,
或者，
M = imaplib.IMAP4_SSL()
M.open( 'imap.gmail.com' )
回答by Tobias Kienzler
Instead of M.login(getpass.getuser([email protected]), getpass.getpass(password))you need to use M.login('[email protected]', 'password'), i.e. plain strings (or better, variables containing them). Your attempt actually shouldn't have worked at all, since getpass's getuserdoesn't take arguments but merely returns the user login name. And [email protected]isn't even a valid variable name (you didn't put it into quotes)...
而不是M.login(getpass.getuser([email protected]), getpass.getpass(password))您需要使用M.login('[email protected]', 'password')，即纯字符串（或更好的，包含它们的变量）。您的尝试实际上根本不应该起作用，因为getpass'sgetuser不接受参数而仅返回用户登录名。而且[email protected]甚至不是一个合法的变量名（你没有把它放到引号）...
