Java Android 2.2 wifi热点API
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Android 2.2 wifi hotspot API
提问by Thomas
What is the API call I need to make in Android 2.2 (Froyo) to create a Wifi hotspot (as seen in the Tethering and Portable Hotspot settings item).
我需要在 Android 2.2 (Froyo) 中调用什么 API 来创建 Wifi 热点(如网络共享和便携式热点设置项中所示)。
采纳答案by markov00
You can call
你可以打电话
private boolean setWifiApEnabled(WifiConfiguration wifiConfig, boolean enabled);
private boolean setWifiApEnabled(WifiConfiguration wifiConfig, boolean enabled);
using reflection :)
使用反射:)
after getting the WifiManager
use the reflection to get the WifiManager
declared methods, look for this method name setWifiApEnabled
and invoke it through the WifiManager
object
获取后WifiManager
使用反射获取WifiManager
声明的方法,查找该方法名setWifiApEnabled
,通过WifiManager
对象调用
These API are marked as @hide, so currently you cannot use them directly, but they appear on the AIDL for the WifiManager so their are accessible!
这些 API 被标记为 @hide,所以目前你不能直接使用它们,但它们出现在 WifiManager 的 AIDL 中,因此它们是可访问的!
An example can be:
一个例子可以是:
WifiManager wifi = (WifiManager) getSystemService(Context.WIFI_SERVICE);
Method[] wmMethods = wifi.getClass().getDeclaredMethods();
for(Method method: wmMethods){
if(method.getName().equals("setWifiApEnabled")){
WifiConfiguration netConfig = new WifiConfiguration();
netConfig.SSID = "\"PROVAAP\"";
netConfig.allowedAuthAlgorithms.set(WifiConfiguration.AuthAlgorithm.OPEN);
netConfig.allowedProtocols.set(WifiConfiguration.Protocol.RSN);
netConfig.allowedProtocols.set(WifiConfiguration.Protocol.WPA);
netConfig.allowedKeyManagement.set(WifiConfiguration.KeyMgmt.WPA_PSK); netConfig.allowedPairwiseCiphers.set(WifiConfiguration.PairwiseCipher.CCMP);
netConfig.allowedPairwiseCiphers.set(WifiConfiguration.PairwiseCipher.TKIP);
netConfig.allowedGroupCiphers.set(WifiConfiguration.GroupCipher.CCMP);
netConfig.allowedGroupCiphers.set(WifiConfiguration.GroupCipher.TKIP);
try {
method.invoke(wifi, netConfig,true);
} catch (IllegalArgumentException e) {
e.printStackTrace();
} catch (IllegalAccessException e) {
e.printStackTrace();
} catch (InvocationTargetException e) {
e.printStackTrace();
}
}
}
It works but I cannot change the current configuration with my own, and getting the current WifiConfiguration of an active AP drive me to an empty configuration.Why?
它可以工作,但我无法使用自己的配置更改当前配置,并且获取活动 AP 的当前 WifiConfiguration 会将我驱动为空配置。为什么?
回答by CommonsWare
There does not appear to be an API call to create a WiFi hotspot -- sorry!
似乎没有创建 WiFi 热点的 API 调用——抱歉!
回答by slinden77
this works on API 8 and above. I use a heavily different version then this below (or above), and was running into the same issue markov00 ran into; not being able to load the default WifiConfiguration for the portable Wi-Fi AP. I found a solution elsewhere.
这适用于 API 8 及更高版本。我使用了一个与下面(或上面)截然不同的版本,并且遇到了 markov00 遇到的相同问题;无法加载便携式 Wi-Fi AP 的默认 WifiConfiguration。我在别处找到了解决方案。
If you like the solution, it would be nice if this was accepted as an answer
如果你喜欢这个解决方案,如果这被接受作为答案会很好
WifiManager wifi = (WifiManager) getSystemService(Context.WIFI_SERVICE);
Method[] wmMethods = wifi.getClass().getDeclaredMethods();
for (Method method: wmMethods){
if (method.getName().equals("setWifiApEnabled")){
try {
// just nullify WifiConfiguration to load the default configuration ;)
method.invoke(wifi, null, true);
} catch (IllegalArgumentException e){
e.printStackTrace();
} catch (IllegalAccessException e){
e.printStackTrace();
} catch (InvocationTargetException e){
e.printStackTrace();
}
}
}