C++ 从 std::cin 读取密码

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时间:2020-08-27 19:52:59  来源:igfitidea点击:

Reading a password from std::cin

c++stlpassword-protection

提问by Vargas

I need to read a password from standard input and wanted std::cinnot to echo the characters typed by the user...

我需要从标准输入中读取密码,并且不想std::cin回显用户输入的字符...

How can I disable the echo from std::cin?

如何禁用 std::cin 的回声?

here is the code that I'm currently using:

这是我目前使用的代码:

string passwd;
cout << "Enter the password: ";
getline( cin, passwd );

I'm looking for a OS agnostic way to do this. Herethere are ways to do this in both Windows and *nix.

我正在寻找一种与操作系统无关的方式来做到这一点。 这里有一些方法可以在 Windows 和 *nix 中执行此操作。

回答by Vargas

@wrang-wrang answer was really good, but did not fulfill my needs, this is what my final code (which was based on this) look like:

@wrang-wrang 答案非常好,但没有满足我的需求,这就是我的最终代码(基于)的样子:

#ifdef WIN32
#include <windows.h>
#else
#include <termios.h>
#include <unistd.h>
#endif

void SetStdinEcho(bool enable = true)
{
#ifdef WIN32
    HANDLE hStdin = GetStdHandle(STD_INPUT_HANDLE); 
    DWORD mode;
    GetConsoleMode(hStdin, &mode);

    if( !enable )
        mode &= ~ENABLE_ECHO_INPUT;
    else
        mode |= ENABLE_ECHO_INPUT;

    SetConsoleMode(hStdin, mode );

#else
    struct termios tty;
    tcgetattr(STDIN_FILENO, &tty);
    if( !enable )
        tty.c_lflag &= ~ECHO;
    else
        tty.c_lflag |= ECHO;

    (void) tcsetattr(STDIN_FILENO, TCSANOW, &tty);
#endif
}

Sample usage:

示例用法:

#include <iostream>
#include <string>

int main()
{
    SetStdinEcho(false);

    std::string password;
    std::cin >> password;

    SetStdinEcho(true);

    std::cout << password << std::endl;

    return 0;
}

回答by Jonathan Graehl

There's nothing in the standard for this.

标准中没有任何内容。

In unix, you could write some magic bytes depending on the terminal type.

在 unix 中,您可以根据终端类型编写一些魔术字节。

Use getpasswdif it's available.

如果可用,请使用 getpasswd

You can system() /usr/bin/stty -echoto disable echo, and /usr/bin/stty echoto enable it (again, on unix).

您可以 system()/usr/bin/stty -echo禁用回声,并/usr/bin/stty echo启用它(再次,在 unix 上)。

This guy explainshow to do it without using "stty"; I didn't try it myself.

这家伙解释了如何在不使用“stty”的情况下做到这一点;我自己没试过。

回答by AraK

If you don't care about portability, you can use _getch()in VC.

如果你不关心便携性,你可以使用_getch()in VC

#include <iostream>
#include <string>
#include <conio.h>

int main()
{
    std::string password;
    char ch;
    const char ENTER = 13;

    std::cout << "enter the password: ";

    while((ch = _getch()) != ENTER)
    {
        password += ch;
        std::cout << '*';
    }
}

There is also getwch()for wide characters. My advice is that you use NCursewhich is available in *nixsystems also.

还有getwch()对于wide characters. 我的建议是,您NCurse也可以使用*nix系统中提供的内容。

回答by IProblemFactory

Only idea what i have, you could read password char by char, and after it just print backspace ("\b") and maybe '*'.

只知道我有什么,您可以逐个字符读取密码字符,然后只打印退格键(“\b”)和“*”。