Bash：从字符串中删除字符直到某个字符
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Bash: Delete characters until a certain character from String
提问by Anne K.
how can I delete characters from a String until a certain character with bash? Example:
如何使用 bash 从字符串中删除字符直到某个字符？例子：
"ananas1kiwi2apple1banana2tree"
shall look like this:
看起来像这样：
"apple1banana2tree"
Thank you!
谢谢！
回答by heemayl
If you want to remove the substring upto 2, using bashparameter expansion:
如果要删除子字符串 upto 2，请使用bash参数扩展：
${var#*2}
#does non-greedy match from left, use##for greediness#*2matches and discards upto first2from variablevar
#从左侧进行非贪婪匹配，##用于贪婪#*2匹配并丢弃2从变量到第一个var
Example:
例子：
$ var='ananas1kiwi2apple1banana2tree'
$ echo "${var#*2}"
apple1banana2tree
回答by Inian
Using pure bashshell parameter expansion.
使用纯bashshell 参数扩展。
$ string="ananas1kiwi2apple1banana2tree"
$ newString="${string#*2}"
$ printf "%s\n" "$newString"
apple1banana2tree
