Java 将 org.w3c.dom.Document 漂亮地打印到标准输出的最短方法是什么？
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What is the shortest way to pretty print a org.w3c.dom.Document to stdout?
提问by flybywire
What is the easiest way to pretty print (a.k.a. formatted) a org.w3c.dom.Documentto stdout?
将 a 漂亮地打印（又名格式化）org.w3c.dom.Document到标准输出的最简单方法是什么？
采纳答案by Bozho
Call printDocument(doc, System.out), where that method looks like this:
调用printDocument(doc, System.out)，该方法如下所示：
public static void printDocument(Document doc, OutputStream out) throws IOException, TransformerException {
TransformerFactory tf = TransformerFactory.newInstance();
Transformer transformer = tf.newTransformer();
transformer.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "no");
transformer.setOutputProperty(OutputKeys.METHOD, "xml");
transformer.setOutputProperty(OutputKeys.INDENT, "yes");
transformer.setOutputProperty(OutputKeys.ENCODING, "UTF-8");
transformer.setOutputProperty("{http://xml.apache.org/xslt}indent-amount", "4");
transformer.transform(new DOMSource(doc),
new StreamResult(new OutputStreamWriter(out, "UTF-8")));
}
(The indent-amountis optional, and might not work with your particular configuration)
（这indent-amount是可选的，可能不适用于您的特定配置）
回答by Dennis
How about:
怎么样：
OutputFormat format = new OutputFormat(doc);
format.setIndenting(true);
XMLSerializer serializer = new XMLSerializer(System.out, format);
serializer.serialize(doc);
回答by hannes
private void printNode(Node rootNode, String spacer) {
System.out.println(spacer + rootNode.getNodeName() + " -> " + rootNode.getNodeValue());
NodeList nl = rootNode.getChildNodes();
for (int i = 0; i < nl.getLength(); i++)
printNode(nl.item(i), spacer + " ");
}
回答by yegor256
回答by Mark
This will return a nicely formated output by using recursive descent/ascent.
这将通过使用递归下降/上升返回格式良好的输出。
private static boolean skipNL;
private static String printXML(Node rootNode) {
String tab = "";
skipNL = false;
return(printXML(rootNode, tab));
}
private static String printXML(Node rootNode, String tab) {
String print = "";
if(rootNode.getNodeType()==Node.ELEMENT_NODE) {
print += "\n"+tab+"<"+rootNode.getNodeName()+">";
}
NodeList nl = rootNode.getChildNodes();
if(nl.getLength()>0) {
for (int i = 0; i < nl.getLength(); i++) {
print += printXML(nl.item(i), tab+" "); // \t
}
} else {
if(rootNode.getNodeValue()!=null) {
print = rootNode.getNodeValue();
}
skipNL = true;
}
if(rootNode.getNodeType()==Node.ELEMENT_NODE) {
if(!skipNL) {
print += "\n"+tab;
}
skipNL = false;
print += "</"+rootNode.getNodeName()+">";
}
return(print);
}
回答by Rockoder
if you use dom4j, it would be dom4JDOM.asString()
如果你使用 dom4j，那就是 dom4JDOM.asString()
