Bash mv 不是目录
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Bash mv not a directory
提问by Jonathan Leffler
I have part of my script that goes like this:
我的脚本的一部分是这样的：
while read line
do
code=`echo ${line} | awk '{print }'`
awk -f ${supscript}/rearrange.sh < ${base}/${code}
mv temp_output* "$code"temp_output*
done < filelist
The script is working; the only problem is that when it is trying to rename the file I got the following error message:
脚本正在运行；唯一的问题是，当它尝试重命名文件时，我收到以下错误消息：
mv: target `pollcodetemp_output*' is not a directory
Maybe it is something related with the IFS. I try to specify this at the beginning of the script as:
也许它与IFS有关。我尝试在脚本的开头将其指定为：
IFS='
'
But it is not working. I'm using a Windows text editor but I have already removed the CR.
但它不起作用。我正在使用 Windows 文本编辑器，但我已经删除了 CR。
回答by Jonathan Leffler
Most likely, you just need:
最有可能的是，您只需要：
mv temp_output* "$code"
This will move the files named temp_output*in the current directory to the directory specified in the variable $code.
这会将temp_output*当前目录中命名的文件移动到变量中指定的目录$code。
However, if $codeis a file, then you need to look for a renamecommand (there are several versions, with different syntaxes), or you need to use an inner loop:
但是，如果$code是文件，则需要查找rename命令（有多个版本，语法不同），或者需要使用内循环：
for file in temp_output*
do mv "$file" "$code$file"
done
回答by lanzz
You are trying to move multiple files to a name that is not a directory, which is not possible. This happens because you seem to be trying to rename from a wildcard pattern toa wildcard pattern, which is also not possible. I won't be guessing what exactly you're trying to accomplish, so I cannot give you any additional advice.
您正在尝试将多个文件移动到非目录名称，这是不可能的。这是因为你似乎是试图从一个通配符模式来重命名到通配符模式，这也是不可能的。我不会猜测你到底想要完成什么，所以我不能给你任何额外的建议。
