bash IP地址转换器
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IP Address Converter
提问by KarlsD
There is IP address: 66.102.13.19, and from this address as that received this address
有IP地址：66.102.13.19，从这个地址收到这个地址
http://1113984275
But how? And how I can make this with the help of bash. For example, this servicecan do it, but I do not understand the algorithm.
但是如何？以及我如何在 bash 的帮助下做到这一点。比如这个服务可以做到，但是我不懂算法。
回答by Paused until further notice.
ip=66.102.13.19
IFS=. read -r a b c d <<< "$ip"
printf '%s%d\n' "http://" "$((a * 256 ** 3 + b * 256 ** 2 + c * 256 + d))"
By the way, the number in your question doesn't match the IP address.
顺便说一下，您问题中的数字与 IP 地址不匹配。
To convert a decimal to an IP:
要将十进制数转换为 IP：
#!/bin/bash
dec2ip () {
local ip dec=$@
for e in {3..0}
do
((octet = dec / (256 ** e) ))
((dec -= octet * 256 ** e))
ip+=$delim$octet
delim=.
done
printf '%s\n' "$ip"
}
dec2ip "$@"
To convert an IP to a decimal:
要将 IP 转换为十进制：
#!/bin/bash
ip2dec () {
local a b c d ip=$@
IFS=. read -r a b c d <<< "$ip"
printf '%d\n' "$((a * 256 ** 3 + b * 256 ** 2 + c * 256 + d))"
}
ip2dec "$@"
Demo:
演示：
$ ./dec2ip 1113984275
66.102.13.19
$ ./ip2dec 66.102.13.19
1113984275
These two scripts rely on features of Bash that aren't present in some Bourne-derived shells. Here are AWK versions to use instead:
这两个脚本依赖于一些 Bourne 派生的 shell 中不存在的 Bash 功能。以下是要使用的 AWK 版本：
#!/usr/bin/awk -f
# dec2ip
BEGIN {
dec = ARGV[1]
for (e = 3; e >= 0; e--) {
octet = int(dec / (256 ^ e))
dec -= octet * 256 ^ e
ip = ip delim octet
delim = "."
}
printf("%s\n", ip)
}
and
和
#!/usr/bin/awk -f
# ip2dec
BEGIN {
ip = ARGV[1]
split(ip, octets, ".")
for (i = 1; i <= 4; i++) {
dec += octets[i] * 256 ** (4 - i)
}
printf("%i\n", dec)
}
They can be called in the same manner as the Bash scripts above.
它们可以以与上述 Bash 脚本相同的方式调用。
回答by Hongbo Liu
IP address -> Number:
IP 地址 -> 号码：
echo 66.102.13.19 | tr . '\n' | awk '{s = s*256 + } END{print s}'
Number -> IP address:
号码 -> IP 地址：
(export ip=1113984275; for i in {1..4}; do s='.'$((ip%256))$s && ((ip>>=8)); done; echo ${s:1})
回答by Isaac
Binary shifting is always faster than multiplying or dividing.
Using a binary AND is faster than mod.
二进制移位总是比乘法或除法快。
使用二进制 AND 比 mod 快。
ip2dec(){ # Convert an IPv4 IP number to its decimal equivalent.
declare -i a b c d;
IFS=. read a b c d <<<"";
echo "$(((a<<24)+(b<<16)+(c<<8)+d))";
}
dec2ip(){ # Convert an IPv4 decimal IP value to an IPv4 IP.
declare -i a=$((~(-1<<8))) b=;
set -- "$((b>>24&a))" "$((b>>16&a))" "$((b>>8&a))" "$((b&a))";
local IFS=.;
echo "$*";
}
ip=66.102.13.19
a=$(ip2dec "$ip")
b=$(dec2ip "$a")
echo "$ip DecIP=$a IPv4=$b "
Note: This system will fail with values like 0008.
Bash thinks it is an octal number.
注意：此系统将失败，并显示类似0008.
Bash 认为它是一个八进制数。
To solve that, each value will have to be cleaned with something like:
为了解决这个问题，每个值都必须用类似的东西来清理：
IsDecInt()( # Is the value given on a decimal integer (with sign)?
declare n=; set --
if [[ $n =~ ^([+-]?)((0)|0*([0-9]*))$ ]]; then
set -- "${BASH_REMATCH[@]:1}"
else
exit 1
fi
echo "";
)
a=$(IsDecInt "$a")||{ Echo "Value $a is not an integer" >&2; exit 1; }
For (very) old shells: bash since 2.04, or dash or any (reasonable) shell:
对于（非常）旧的 shell：bash 自 2.04 或 dash 或任何（合理的）shell：
ip2dec(){ # Convert an IPv4 IP number to its decimal equivalent.
local a b c d;
IFS=. read a b c d <<-_EOF_
_EOF_
echo "$(((a<<24)+(b<<16)+(c<<8)+d))";
}
dec2ip(){ # Convert an IPv4 decimal IP value to an IPv4 IP.
local a=$((~(-1<<8))) b=;
set -- "$((b>>24&a))" "$((b>>16&a))" "$((b>>8&a))" "$((b&a))";
local IFS=.;
echo "$*";
}
ip=
a=$(ip2dec "$ip")
b=$(dec2ip "$a")
echo "$ip DecIP=$a IPv4=$b "
回答by vik
my version for int to ip conversion:
我的 int 到 ip 转换版本：
echo 3232235521| awk {'print rshift(and($1, 0xFF000000), 24) "." rshift(and($1, 0x00FF0000), 16) "." rshift(and($1, 0x0000FF00), 8) "." and($1, 0x000000FF) '}
echo 3232235521| awk {'print rshift(and($1, 0xFF000000), 24) "." rshift(and($1, 0x00FF0000), 16) "." rshift(and($1, 0x0000FF00), 8) "." and($1, 0x000000FF) '}
回答by evuraan
Here's my take:
这是我的看法：
$ host google.com
google.com has address 216.58.216.142
$ ./ip2d.sh 216.58.216.142
3627735182
$ ./d2ip.sh 3627735182
216.58.216.142
ip2d.sh:
ip2d.sh:
#!/bin/bash
IFS=.
set -- $*
echo $(( (*256**3) + (*256**2) + (*256) + () ))
d2ip.sh:
d2ip.sh：
#!/bin/bash
IFS=" " read -r a b c d <<< $(echo "obase=256 ; " |bc)
echo ${a#0}.${b#0}.${c#0}.${d#0}
回答by Brian Chrisman
I think there's a simpler solution that also handles an arbitrary number of octets with no references to fixed offsets etc.
我认为有一个更简单的解决方案，它也可以处理任意数量的八位字节，而没有对固定偏移量的引用等。
echo 66.102.13.19 |
tr . '\n' |
while read octet; do
printf "%.08d" $(echo "obase=2;$octet" | bc)
done |
echo $((2#$(cat)))
output: 1113984275
输出：1113984275
回答by ken
Simple int to IP conversion for bash
bash 的简单 int 到 IP 转换
dec2ip ()
{
local v=
local i1=$((v>>24&255))
local i2=$((v>>16&255))
local i3=$((v>>8&255))
local i4=$((v&255))
printf '%d.%d.%d.%d\n' $i1 $i2 $i3 $i4
}
