Python:抽象类 __init__

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时间:2020-08-20 00:28:57  来源:igfitidea点击:

Python: abstract class __init__

pythonpython-2.7oopabstract-class

提问by dabadaba

I am trying to declare an abstract class Awith a constructor with a default behavior: all subclasses must initialize a member self.n:

我正在尝试A使用具有默认行为的构造函数声明一个抽象类:所有子类都必须初始化一个成员self.n

from abc import ABCMeta

class A(object):
    __metaclass__ = ABCMeta

    def __init__(self, n):
        self.n = n

However, I do not want to let the Aclass be instantiated because, well, it is an abstract class. The problem is, this is actually allowed:

但是,我不想让A类被实例化,因为它是一个抽象类。问题是,这实际上是允许的:

a = A(3)

This produces no errors, when I would expect it should.

这不会产生错误,而我希望它应该。

So: how can I define an un-instantiable abstract class while defining a default behavior for the constructor?

那么:如何在为构造函数定义默认行为的同时定义不可实例化的抽象类?

回答by Mike Müller

Making the __init__an abstract method:

使__init__抽象方法:

from abc import ABCMeta, abstractmethod

class A(object):
    __metaclass__ = ABCMeta

    @abstractmethod
    def __init__(self, n):
        self.n = n


if __name__ == '__main__':
    a = A(3)

helps:

帮助:

TypeError: Can't instantiate abstract class A with abstract methods __init__

Python 3 version:

Python 3 版本:

from abc import ABCMeta, abstractmethod

class A(object, metaclass=ABCMeta):

    @abstractmethod
    def __init__(self, n):
        self.n = n


if __name__ == '__main__':
    a = A(3)

Works as well:

也有效:

TypeError: Can't instantiate abstract class A with abstract methods __init__

回答by gipsy

A not so elegant solution can be this:

一个不太优雅的解决方案可能是这样的:

class A(object):
  def __init__(self, n):
    if self.__class__ == A:
      raise Exception('I am abstract!')
    self.n = n

Usage

用法

class B(A):
  pass
a = A(1)  # Will throw exception
b = B(1)  # Works fine as expected.

回答by Ignacio Vergara Kausel

You should define the methods as abstract as well with the @abc.abstractmethoddecorator.

您应该使用@abc.abstractmethod装饰器将方法定义为抽象方法。

回答by Ashwini Chaudhary

You can override __new__method to prevent direct instantiation.

您可以覆盖__new__方法以防止直接实例化。

class A(object):
    __metaclass__ = ABCMeta

    def __new__(cls, *args, **kwargs):
        if cls is A:
            raise TypeError(
                "TypeError: Can't instantiate abstract class {name} directly".format(name=cls.__name__)
            )
        return object.__new__(cls)

Output:

输出:

>>> A()
Traceback (most recent call last):
  File "<ipython-input-8-3cd318a12eea>", line 1, in <module>
    A()
  File "/Users/ashwini/py/so.py", line 11, in __new__
    "TypeError: Can't instantiate abstract class {name} directly".format(name=cls.__name__)
TypeError: TypeError: Can't instantiate abstract class A directly

回答by Tiger

You can implement something like below :

您可以实现如下内容:

from abc import ABC
class A(ABC):
    def __init__(self, n):
        self.n = n
        super(A,self).__init__()

Instantiating this class would throw an error

实例化这个类会抛出一个错误