将单个数字转换为单个数字 Python
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Turn a single number into single digits Python
提问by user3221242
I want to make a number , for example 43365644 into single numbers [4,3,3....,4,4]
我想把一个数字，例如 43365644 变成单个数字 [4,3,3....,4,4]
and append it on a list
并将其附加到列表中
回答by user3221242
This can be done quite easily if you:
如果您：
Use
strto convert the number into a string so that you can iterate over it.Use a list comprehensionto split the string into individual digits.
Use
intto convert the digits back into integers.
Below is a demonstration:
下面是一个演示：
>>> n = 43365644
>>> [int(d) for d in str(n)]
[4, 3, 3, 6, 5, 6, 4, 4]
>>>
回答by Slater Victoroff
If you want to change your number into a list of those numbers, I would first cast it to a string, then casting it to a list will naturally break on each character:
如果您想将您的数字更改为这些数字的列表，我会先将其转换为 a string，然后将其转换为列表自然会在每个字符上中断：
[int(x) for x in str(n)]
回答by Maxime Lorant
The easiest way is to turn the int into a string and take each character of the string as an element of your list:
最简单的方法是将 int 转换为字符串并将字符串的每个字符作为列表的元素：
>>> n = 43365644
>>> digits = [int(x) for x in str(n)]
>>> digits
[4, 3, 3, 6, 5, 6, 4, 4]
>>> lst.extend(digits) # use the extends method if you want to add the list to another
It involves a casting operation, but it's readable and acceptable if you don't need extreme performance.
它涉及强制转换操作，但如果您不需要极端性能，它是可读且可接受的。
回答by inspectorG4dget
Here's a way to do it without turning it into a string first (based on some rudimentary benchmarking, this is about twice as fast as stringifying nfirst):
这是一种无需先将其转换为字符串的方法（基于一些基本的基准测试，这大约是n先字符串化的两倍）：
>>> n = 43365644
>>> [(n//(10**i))%10 for i in range(math.ceil(math.log(n, 10))-1, -1, -1)]
[4, 3, 3, 6, 5, 6, 4, 4]
