windows require_once 和 include_once 无法正确解析文件
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require_once and include_once not resolving files correctly
提问by Ian Cant
Am having problems with PHP's require_once, require, include_once and include functions not correctly resolving a file. I am running PHP 5.3.1 on Windows Vista with Apache 2.2.11.
我遇到了 PHP 的 require_once、require、include_once 和 include 函数无法正确解析文件的问题。我在带有 Apache 2.2.11 的 Windows Vista 上运行 PHP 5.3.1。
These are the problems I am getting:
这些是我遇到的问题：
file_exists('C:/wamp/www/park_factor_network/system/application/shared/config/language.php')
returns TRUE
返回真
is_readable('system/application/shared/config/language.php')
returns TRUE
返回真
$fp = fopen('C:/wamp/www/park_factor_network/system/application/shared/config/language.php','r');
$contents = fread($fp, filesize('C:/wamp/www/park_factor_network/system/application/shared/config/language.php'));
returns a valid file resource and stores it into $contents
返回一个有效的文件资源并将其存储到 $contents
However:
然而：
require_once('system/application/shared/config/database.php') or die("Cannot Include Language Config");
require_once('C:/wamp/www/park_factor_network/system/application/shared/config/language.php') or die("Cannot Include Language Config");
return:
返回：
Fatal error: require_once() [function.require]: Failed opening required '1' (include_path='.;C:\php5\pear') in C:\wamp\www\park_factor_network\system\application\shared\hooks\select_language.php on line 25
C:\wamp\www\park_factor_network\system\application\news_site\hooks is a Directory Junction for C:\wamp\www\park_factor_network\system\application\shared\hooks
C:\wamp\www\park_factor_network\system\application\news_site\hooks 是 C:\wamp\www\park_factor_network\system\application\shared\hooks 的目录连接
I only experience this problem when accessing this file from a certain location in the framework, however as this is a direct include or require it shouldn't be affected by that and only PHP? If I try and include the file anywhere else within my setup it loads fine.
我只在从框架中的某个位置访问这个文件时遇到这个问题，但是因为这是一个直接包含或要求它不应该受那个影响，只有 PHP？如果我尝试将文件包含在我的设置中的其他任何地方，它加载得很好。
回答by Pekka
require_onceis a language construct. It is not a function and has no return value.
require_once是一种语言结构。它不是一个函数，也没有返回值。
Brackets around the file name parameter are optional. This seems to mean that in this line:
文件名参数周围的括号是可选的。这似乎意味着在这一行中：
require_once('system/application/shared/config/database.php')
or die("Cannot Include Language Config");
the whole expression
整个表达
('system/application/shared/config/database.php')
or die("Cannot Include Language Config");
is evaluated (returning 1) and used as the file name argument. 1, obviously, doesn't exist.
被评估（返回1）并用作文件名参数。1，显然，不存在。
What you are doing doesn't make real sense though, because includewill not return falsewhen loading a file fails. require_once()will terminate the script's execution anyway. If you take care of switching of error reporting in your production environment, you could easily live with a PHP Fatal Error telling you the file doesn't exist (instead of your custom die()).
但是，您正在做的事情没有实际意义，因为加载文件失败时include不会返回false。require_once()无论如何都会终止脚本的执行。如果您在生产环境中处理错误报告的切换，您很容易接受一个 PHP 致命错误，告诉您该文件不存在（而不是您的自定义die()）。
If you needto gracefully exit the script, I would do a file_existscall before the statement, and die()when that fails:
如果你需要优雅地退出脚本，我会file_exists在语句之前调用，die()当调用失败时：
$file = 'system/application/shared/config/database.php';
if ((!is_file($file)) or(!is_readable($file)))
die("Cannot Include Language Config");
require_once('system/application/shared/config/database.php');
