string 如何从shell字符串中剪切最后一个字段
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How to cut the last field from a shell string
提问by user558134
How to cut the last field in this shell string
如何剪切此 shell 字符串中的最后一个字段
LINE="/string/to/cut.txt"
So that the string would look like this
所以字符串看起来像这样
LINE="/string/to/"
Thanks in advance!
提前致谢！
采纳答案by user554272
I think you could use the "dirname" command. It takes in input a file path, removes the filename part and returns the path. For example:
我认为您可以使用“dirname”命令。它接受输入文件路径，删除文件名部分并返回路径。例如：
$ dirname "/string/to/cut.txt"
/string/to
回答by Lucas Jones
For what it's worth, a cut-based solution:
对于它的价值，cut基于 - 的解决方案：
NEW_LINE="`echo "$LINE" | rev | cut -d/ -f2- | rev`/"
回答by Paused until further notice.
This will work in modern Bourne versions such as Dash, BusyBox ash, etc., as well as descendents such as Bash, Korn shell and Z shell.
这将适用于现代 Bourne 版本，例如 Dash、BusyBox ash 等，以及 Bash、Korn shell 和 Z shell 等后代。
LINE="/string/to/cut.txt"
LINE=${LINE%/*}
or to keep the final slash:
或保留最后的斜线：
LINE=${LINE%/*}/
回答by ajreal
echo "/string/to/cut.txt" | awk -F'/' '{for (i=1; i<NF; i++) printf("%s/", $i)}'
回答by mohit6up
echo $LINE | grep -o '.*/'works too.
echo $LINE | grep -o '.*/'也有效。
