java BigInteger(long) 在 BigInteger 中有私有访问权限
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BigInteger(long) has private access in BigInteger
提问by Sunil Kumar
I am trying to store a big calculation in a BigInteger instance. I tried this :
我正在尝试在 BigInteger 实例中存储一个大计算。我试过这个：
BigInteger answer=new BigInteger(2+3);
and got the following error :
并得到以下错误：
temp.java:17: error: BigInteger(long) has private access in BigInteger
BigInteger answer=new BigInteger(2+3);
^
1 error
I know that instead of "2+3" there should be a string value. But i don't know how to satisfy that condition(assuming that i don't how much 2+3 is). Please tell me how to assign a calculated value to BigInteger object(assign 2+3 to BigInteger answer).
我知道应该有一个字符串值而不是“2+3”。但我不知道如何满足这个条件（假设我不知道 2+3 是多少）。请告诉我如何将计算值分配给 BigInteger 对象（将 2+3 分配给 BigInteger 答案）。
回答by Jon Skeet
If you want to perform the arithmetic using BigInteger, you should create a BigIntegerfor each value and then use BigInteger.add. However, you don'tneed to use strings to do that. You may want to if your input is already a string and it might be long, but if you've already got a long, you can use BigInteger.valueOf. For example:
如果要使用 执行算术BigInteger，则应BigInteger为每个值创建一个，然后使用BigInteger.add. 但是，你不要需要使用字符串来做到这一点。如果您的输入已经是一个字符串并且它可能很长，您可能想要，但是如果您已经有一个long，则可以使用BigInteger.valueOf. 例如：
BigInteger answer = BigInteger.valueOf(2).add(BigInteger.valueOf(3));
I certainly wouldn't convert a longinto a Stringjust to then pass it into the BigIntegerconstructor.
我当然不会将 a 转换long为 aString然后将其传递给BigInteger构造函数。
回答by Hovercraft Full Of Eels
You could just use BigInteger's add(...)method:
你可以只使用 BigInteger 的add(...)方法：
BigInteger answer = new BigInteger("2").add(new BigInteger("3"));
No worries about overflow with this solution.
无需担心此解决方案会溢出。
