jQuery.ajax 返回 400 Bad Request
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jQuery.ajax returns 400 Bad Request
提问by Scott B
This works fine:
这工作正常：
jQuery('#my_get_related_keywords').click(function() {
if (jQuery('#my_keyword').val() == '') return false;
jQuery.getJSON("http://boss.yahooapis.com/ysearch/web/v1/"
+jQuery('#my_keyword').val()+"?"
+"appid=myAppID"
+"&lang=en"
+"&format=json"
+"&count=50"
+"&view=keyterms"
+"&callback=?",
function (data) {//do something}
This returns 400 Bad Request (Just a reformulation of the above jQuery using .ajax to support error handling).
这将返回 400 Bad Request（只是使用 .ajax 支持错误处理的上述 jQuery 的重构）。
jQuery('#my_get_related_keywords').click(function()
{
if (jQuery('#my_keyword').val() == '') return false;
jQuery('#my_loader').show();
jQuery.ajax(
{
url: "http://boss.yahooapis.com/ysearch/web/v1/"
+jQuery('#my_keyword').val()+"?"
+"appid=myAppID"
+"&lang=en"
+"&format=json"
+"&count=50"
+"&view=keyterms"
+"&callback=?",
success: function(data)
{//do something}
回答by Andrea Turri
I think you just need to add 2 more options (contentTypeand dataType):
我认为您只需要再添加 2 个选项（contentType和dataType）：
$('#my_get_related_keywords').click(function() {
$.ajax({
type: "POST",
url: "HERE PUT THE PATH OF YOUR SERVICE OR PAGE",
data: '{"HERE YOU CAN PUT DATA TO PASS AT THE SERVICE"}',
contentType: "application/json; charset=utf-8", // this
dataType: "json", // and this
success: function (msg) {
//do something
},
error: function (errormessage) {
//do something else
}
});
}
回答by light
Add this to your ajax call:
将此添加到您的 ajax 调用中：
contentType: "application/json; charset=utf-8",
dataType: "json"
回答by bhietpas
Late answer, but I figured it's worth keeping this updated. Expanding on Andrea Turri answer to reflect updated jQuery API and .success/.error deprecated methods.
迟到的答案，但我认为值得更新。扩展 Andrea Turri 的答案以反映更新的 jQuery API 和 .success/.error 不推荐使用的方法。
As of jQuery 1.8.* the preferred way of doing this is to use .done() and .fail(). Jquery Docs
从 jQuery 1.8.* 开始，这样做的首选方法是使用 .done() 和 .fail()。jQuery 文档
e.g.
例如
$('#my_get_related_keywords').click(function() {
var ajaxRequest = $.ajax({
type: "POST",
url: "HERE PUT THE PATH OF YOUR SERVICE OR PAGE",
data: '{"HERE YOU CAN PUT DATA TO PASS AT THE SERVICE"}',
contentType: "application/json; charset=utf-8",
dataType: "json"});
//When the request successfully finished, execute passed in function
ajaxRequest.done(function(msg){
//do something
});
//When the request failed, execute the passed in function
ajaxRequest.fail(function(jqXHR, status){
//do something else
});
});
回答by Nelles
Be sure and use 'get' or 'post' consistantly with your $.ajax call for example.
例如，请确保在 $.ajax 调用中始终使用“get”或“post”。
$.ajax({
type: 'get',
must be met with
必须遇到
app.get('/', function(req, res) {
app.get('/', function(req, res) {
=============== and for post
================ 和帖子
$.ajax({ type: 'post',
$.ajax({ type: 'post',
must be met with
必须遇到
app.post('/', function(req, res) {
