Java 如何将 JSON 对象从 POSTMAN 发送到 Restful webservices
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How to send JSON Object from POSTMAN to Restful webservices
提问by dev777
I'm trying to send json from POSTMAN to RESTful webservice. I had followed this tutorial urlfor sending json through POSTMAN.
我正在尝试将 json 从 POSTMAN 发送到 RESTful web 服务。我已经按照本教程url通过 POSTMAN 发送 json。
My URL :
我的网址：
http://localhost:8080/myWebService/rest/dataInsert/insert
http://localhost:8080/myWebService/rest/dataInsert/insert
My Service method:
我的服务方式：
@POST
@Path("/insert")
@Consumes(MediaType.APPLICATION_JSON)
public String insertData(JSONObject jsonlist) throws UnknownHostException;
My Impl:
我的实现：
@Override
public String insertData(JSONObject jsonlist) throws UnknownHostException {
System.out.println(jsonlist);
insertDataDao.insertData(jsonlist);
return "SUCCESS";
}
My DAO:
我的道：
public String insertData(JSONObject jsonlist) throws UnknownHostException{
System.out.println(jsonlist);
MongoConnection mongoconnection = new MongoConnection();
MongoClient mongoclient = mongoconnection.getMongoClient();
MongoDatabase db = mongoclient.getDatabase("mydb");
MongoCollection<Document> col = db.getCollection("col");
String jsonString = jsonlist.toString();
System.out.println(jsonString);
Document doc = Document.parse(jsonString);
col.insertOne(doc);
System.out.println("Inserted Successfully !!!");
return "SUCCESS";
}
But I'm facing the below Exception:
但我面临以下异常：
JBWEB000236: Servlet.service() for servlet CXFServlet threw exception: java.lang.NoSuchMethodError: javax.ws.rs.InternalServerErrorException.validate(Ljavax/ws/rs/core/Response;Ljavax/ws/rs/core/Response$Status;)Ljavax/ws/rs/core/Response;
JBWEB000236：servlet CXFServlet 的 Servlet.service() 抛出异常：java.lang.NoSuchMethodError: javax.ws.rs.InternalServerErrorException.validate(Ljavax/ws/rs/core/Response;Ljavax/ws/rs/core/Response$Status ;)Ljavax/ws/rs/core/Response;
I'm unable to fix this issue. Can anyone please help me out regarding this ...
我无法解决这个问题。任何人都可以帮我解决这个问题...
回答by Arnish gupta
Step 1: open postman type your api url and select post type.
第 1 步：打开邮递员，输入您的 api 网址并选择帖子类型。
Step 2: goto Headers button type("Content-Type") first input box and type "application/json" in second input box it gives auto-complete suggestion
第 2 步：转到 Headers button type("Content-Type") 第一个输入框并在第二个输入框中输入“application/json”它会给出自动完成建议
Step 3: goto Body button and choose raw radio button and choose JSON (application/json) in drop down in same raw right side.
第 3 步：转到正文按钮并选择原始单选按钮，然后在相同原始右侧的下拉列表中选择 JSON (application/json)。
Step 4: type your json like student object
第 4 步：像 student 对象一样输入你的 json
{
"name": "dummy",
"marks": "26"
}
回答by Rahamath
POSTMAN V5.2.0 Testing
POSTMAN V5.2.0 测试
URL: http://localhost:8080/mail/user/register/
网址：http://localhost:8080/mail/user/register/
JSON Data:
JSON 数据：
{"name":"John","firstName":"Smith","lastName":"MT","email":"[email protected]"}
Steps:
脚步：
- Add in Headers
- 添加标题
key: content-type
value: application/json
Paste above JSON data by click
BODY->raw->JSON (application/json)Click send and see the response text in JSON/XML....
通过单击粘贴上面的 JSON 数据
BODY->raw->JSON (application/json)单击发送并查看 JSON/XML 格式的响应文本....
NOTE:
笔记：
- user refers in the URL your REST Spring controller
- 用户在 URL 中引用您的 REST Spring 控制器
@RestController
@RequestMapping("/user")
- register refers in the URL
- 注册在 URL 中引用
@RequestMapping(value = "/register", method = RequestMethod.POST, produces="application/json", consumes="application/json")
回答by GGEv
I had the same problem which was solved by importing the jersey.jsondependency first and then adding this in web.xml
我遇到了同样的问题，通过先导入jersey.json依赖项然后将其添加到web.xml
<init-param>
<param-name>com.sun.jersey.api.json.POJOMappingFeature</param-name>
<param-value>true</param-value>
</init-param>
