java 操作 IP 地址 - 在 '.' 上拆分字符串 特点
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Manipulating IP addresses - split string on '.' character
提问by WassiM ZgheiB
String address = "192.168.1.1";
I want to split the address and the delimiter is the point. So I used this code:
我想拆分地址，分隔符是重点。所以我使用了这个代码：
String [] split = address.split(".");
But it didn't work, when I used this code it works:
但它不起作用，当我使用此代码时，它起作用了：
String [] split = address.split("\.");
so why splitting the dot in IPv4 address is done like this : ("\\.")?
那么为什么在 IPv4 地址中拆分点是这样完成的：("\\.")？
回答by Boris the Spider
You need to escape the "." as splittakes a regex. But you also need to escape the escape as "\." won't work in a java String:
你需要转义“。” assplit需要一个正则表达式。但是您还需要将转义符转义为“\”。在 java 中不起作用String：
String [] split = address.split("\.");
This is because the backslash in a java Stringdenotes the beginning of a character literal.
这是因为 java 中的反斜杠String表示字符文字的开头。
回答by sol4me
You should split like this, small tip use Pattern.compile as well
你应该像这样拆分，小技巧也使用Pattern.compile
String address = "192.168.1.1";
String[] split = address.split("\.");// you can replace it with private static final Pattern.
