Java 如何从 Android 进行 HTTPS POST?
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How to do an HTTPS POST from Android?
提问by Dino Mycle
I want to do a HTTPS post method to send some data from my android app to my website.
我想做一个 HTTPS 发布方法,将一些数据从我的 android 应用程序发送到我的网站。
I used HttpURLConnection
first and it's working fine with my HTTP URL. My production website is on HTTPS and I want to send the same POST using HttpsURLConnection
. Can someone help me use the class properly?
我HttpURLConnection
首先使用它,它在我的 HTTP URL 上运行良好。我的生产网站使用 HTTPS,我想使用HttpsURLConnection
. 有人可以帮助我正确使用课程吗?
I found some source at this link:
我在这个链接上找到了一些来源:
KeyStore keyStore = ...;
TrustManagerFactory tmf = TrustManagerFactory.getInstance("X509");
tmf.init(keyStore);
SSLContext context = SSLContext.getInstance("TLS");
context.init(null, tmf.getTrustManagers(), null);
URL url = new URL("https://www.example.com/");
HttpsURLConnection urlConnection = (HttpsURLConnection)
url.openConnection();
urlConnection.setSSLSocketFactory(context.getSocketFactory());
InputStream in = urlConnection.getInputStream();
What should be the value of KeyStore keyStore = ...;
?
应该是什么值 KeyStore keyStore = ...;
?
I tried sending the data using the same HttpURLConnection
, but I am seeing some POST data is missed or in error.
我尝试使用相同的 发送数据 HttpURLConnection
,但我看到一些 POST 数据丢失或错误。
I've tried the method from this question. I am pasting my code below
我已经尝试过这个问题的方法。我在下面粘贴我的代码
String urlParameters="dateTime=" + URLEncoder.encode(dateTime,"UTF-8")+
"&mobileNum="+URLEncoder.encode(mobileNum,"UTF-8");
URL url = new URL(myurl);
HttpsURLConnection conn;
conn=(HttpsURLConnection)url.openConnection();
// Create the SSL connection
SSLContext sc;
sc = SSLContext.getInstance("TLS");
sc.init(null, null, new java.security.SecureRandom());
conn.setSSLSocketFactory(sc.getSocketFactory());
conn.setConnectTimeout(HTTP_CONNECT_TIME_OUT);
conn.setReadTimeout(HTTP_READ_TIME_OUT);
//set the output to true, indicating you are outputting(uploading) POST data
conn.setDoOutput(true);
//once you set the output to true, you don't really need to set the request method to post, but I'm doing it anyway
conn.setRequestMethod("POST");
conn.setFixedLengthStreamingMode(urlParameters.getBytes().length);
conn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
PrintWriter out = new PrintWriter(conn.getOutputStream());
out.print(urlParameters);
out.close();
InputStream is = conn.getInputStream();
BufferedReader in = new BufferedReader(new InputStreamReader(is));
String inputLine;
while ((inputLine = in.readLine()) != null) {
response += inputLine;
}
The error I am getting is below:
我得到的错误如下:
05-12 19:36:10.758: W/System.err(1123): java.io.FileNotFoundException: https://www.myurl.com/fms/test
05-12 19:36:10.758: W/System.err(1123): at libcore.net.http.HttpURLConnectionImpl.getInputStream(HttpURLConnectionImpl.java:177)
05-12 19:36:10.758: W/System.err(1123): at libcore.net.http.HttpsURLConnectionImpl.getInputStream(HttpsURLConnectionImpl.java:270)
05-12 19:36:10.758: W/System.err(1123): at .httpRequest(SMSToDBService.java:490)
05-12 19:36:10.758: W/System.err(1123): at com..accessprivate InputStream getInputStream(String urlStr, String user, String password) throws IOException
{
URL url = new URL(urlStr);
HttpsURLConnection conn = (HttpsURLConnection) url.openConnection();
// Create the SSL connection
SSLContext sc;
sc = SSLContext.getInstance("TLS");
sc.init(null, null, new java.security.SecureRandom());
conn.setSSLSocketFactory(sc.getSocketFactory());
// Use this if you need SSL authentication
String userpass = user + ":" + password;
String basicAuth = "Basic " + Base64.encodeToString(userpass.getBytes(), Base64.DEFAULT);
conn.setRequestProperty("Authorization", basicAuth);
// set Timeout and method
conn.setReadTimeout(7000);
conn.setConnectTimeout(7000);
conn.setRequestMethod("POST");
conn.setDoInput(true);
// Add any data you wish to post here
conn.connect();
return conn.getInputStream();
}
(SMSToDBService.java:424)
05-12 19:36:10.758: W/System.err(1123): at com.$ChildThread.handleMessage(SMSToDBService.java:182)
05-12 19:36:10.758: W/System.err(1123): at android.os.Handler.dispatchMessage(Handler.java:99)
05-12 19:36:10.758: W/System.err(1123): at android.os.Looper.loop(Looper.java:156)
05-12 19:36:10.758: W/System.err(1123): at com.$ChildThread.run(SMSToDBService.java:303)
采纳答案by tbkn23
You can use the default CAs that are defined in the android device, which is just fine for any public web.
您可以使用在 android 设备中定义的默认 CA,这适用于任何公共网络。
If you have a self-signed certificate, you can either accept all certificates (risky, open to man-in-the-middle attacks) or create your own TrustManagerFactory
, which is a bit out of this scope.
如果您有自签名证书,您可以接受所有证书(有风险,容易受到中间人攻击)或创建自己的TrustManagerFactory
.
Here's some code to use the default CAs for a https POST call:
下面是一些使用默认 CA 进行 https POST 调用的代码:
String result = new String();
InputStream is = getInputStream(urlStr, user, password);
BufferedReader in = new BufferedReader(new InputStreamReader(is));
String inputLine;
while ((inputLine = in.readLine()) != null) {
result += inputLine;
}
To read the response:
阅读回复:
public class EasySSLSocketFactory implements SocketFactory, LayeredSocketFactory {
private SSLContext sslcontext = null;
private static SSLContext createEasySSLContext() throws IOException {
try {
SSLContext context = SSLContext.getInstance("TLS");
context.init(null, new TrustManager[] { new EasyX509TrustManager(null) }, null);
return context;
} catch (Exception e) {
throw new IOException(e.getMessage());
}
}
private SSLContext getSSLContext() throws IOException {
if (this.sslcontext == null) {
this.sslcontext = createEasySSLContext();
}
return this.sslcontext;
}
/**
* @see org.apache.http.conn.scheme.SocketFactory#connectSocket(java.net.Socket, java.lang.String, int,
* java.net.InetAddress, int, org.apache.http.params.HttpParams)
*/
public Socket connectSocket(Socket sock, String host, int port, InetAddress localAddress, int localPort,
HttpParams params) throws IOException, UnknownHostException, ConnectTimeoutException {
int connTimeout = HttpConnectionParams.getConnectionTimeout(params);
int soTimeout = HttpConnectionParams.getSoTimeout(params);
InetSocketAddress remoteAddress = new InetSocketAddress(host, port);
SSLSocket sslsock = (SSLSocket) ((sock != null) ? sock : createSocket());
if ((localAddress != null) || (localPort > 0)) {
// we need to bind explicitly
if (localPort < 0) {
localPort = 0; // indicates "any"
}
InetSocketAddress isa = new InetSocketAddress(localAddress, localPort);
sslsock.bind(isa);
}
sslsock.connect(remoteAddress, connTimeout);
sslsock.setSoTimeout(soTimeout);
return sslsock;
}
/**
* @see org.apache.http.conn.scheme.SocketFactory#createSocket()
*/
public Socket createSocket() throws IOException {
return getSSLContext().getSocketFactory().createSocket();
}
/**
* @see org.apache.http.conn.scheme.SocketFactory#isSecure(java.net.Socket)
*/
public boolean isSecure(Socket socket) throws IllegalArgumentException {
return true;
}
/**
* @see org.apache.http.conn.scheme.LayeredSocketFactory#createSocket(java.net.Socket, java.lang.String, int,
* boolean)
*/
public Socket createSocket(Socket socket, String host, int port, boolean autoClose) throws IOException,
UnknownHostException {
return getSSLContext().getSocketFactory().createSocket(socket, host, port, autoClose);
}
// -------------------------------------------------------------------
// javadoc in org.apache.http.conn.scheme.SocketFactory says :
// Both Object.equals() and Object.hashCode() must be overridden
// for the correct operation of some connection managers
// -------------------------------------------------------------------
public boolean equals(Object obj) {
return ((obj != null) && obj.getClass().equals(EasySSLSocketFactory.class));
}
public int hashCode() {
return EasySSLSocketFactory.class.hashCode();
}
}
回答by Emil Adz
You can take a look at this question I asked a few days ago:
你可以看看我前几天问的这个问题:
Change HTTP post request to HTTPS post request:
将 HTTP post 请求更改为 HTTPS post 请求:
I have supplied there a solution that worked for me, that basically accepts any self-signed certificate. As been said here this solution is not recommended as it's not secure and open to a man-in-the-middle attacks.
我在那里提供了一个对我有用的解决方案,它基本上接受任何自签名证书。正如此处所说,不建议使用此解决方案,因为它不安全且容易受到中间人攻击。
Here is the code:
这是代码:
EasySSLSocketFactory:
EasySSLSocketFactory:
public class EasyX509TrustManager implements X509TrustManager {
private X509TrustManager standardTrustManager = null;
/**
* Constructor for EasyX509TrustManager.
*/
public EasyX509TrustManager(KeyStore keystore) throws NoSuchAlgorithmException, KeyStoreException {
super();
TrustManagerFactory factory = TrustManagerFactory.getInstance(TrustManagerFactory.getDefaultAlgorithm());
factory.init(keystore);
TrustManager[] trustmanagers = factory.getTrustManagers();
if (trustmanagers.length == 0) {
throw new NoSuchAlgorithmException("no trust manager found");
}
this.standardTrustManager = (X509TrustManager) trustmanagers[0];
}
/**
* @see javax.net.ssl.X509TrustManager#checkClientTrusted(X509Certificate[],String authType)
*/
public void checkClientTrusted(X509Certificate[] certificates, String authType) throws CertificateException {
standardTrustManager.checkClientTrusted(certificates, authType);
}
/**
* @see javax.net.ssl.X509TrustManager#checkServerTrusted(X509Certificate[],String authType)
*/
public void checkServerTrusted(X509Certificate[] certificates, String authType) throws CertificateException {
if ((certificates != null) && (certificates.length == 1)) {
certificates[0].checkValidity();
} else {
standardTrustManager.checkServerTrusted(certificates, authType);
}
}
/**
* @see javax.net.ssl.X509TrustManager#getAcceptedIssuers()
*/
public X509Certificate[] getAcceptedIssuers() {
return this.standardTrustManager.getAcceptedIssuers();
}
}
EasyX509TrustManager:
EasyX509信任管理器:
public static HttpClient getNewHttpClient() {
try {
KeyStore trustStore = KeyStore.getInstance(KeyStore.getDefaultType());
trustStore.load(null, null);
SSLSocketFactory sf = new MySSLSocketFactory(trustStore);
sf.setHostnameVerifier(SSLSocketFactory.ALLOW_ALL_HOSTNAME_VERIFIER);
HttpParams params = new BasicHttpParams();
HttpProtocolParams.setVersion(params, HttpVersion.HTTP_1_1);
HttpProtocolParams.setContentCharset(params, HTTP.UTF_8);
SchemeRegistry registry = new SchemeRegistry();
registry.register(new Scheme("http", PlainSocketFactory.getSocketFactory(), 80));
registry.register(new Scheme("https", sf, 443));
ClientConnectionManager ccm = new ThreadSafeClientConnManager(params, registry);
return new DefaultHttpClient(ccm, params);
} catch (Exception e) {
return new DefaultHttpClient();
}
}
And I added this method: getNewHttpClient()
我添加了这个方法:getNewHttpClient()
DefaultHttpClient client = new DefaultHttpClient();
Finally for every place in my code that I had:
最后,对于我代码中的每个地方:
HttpClient client = getNewHttpClient();
I replace it with:
我将其替换为:
@Override
public String sendHttpRequest(String params) {
String result = "";
try {
URL url = new URL(AUTHENTICATION_SERVER_ADDRESS);
HttpsURLConnection connection = (HttpsURLConnection) url.openConnection();
connection.setSSLSocketFactory(KeyPinStore.getInstance().getContext().getSocketFactory()); // Tell the URLConnection to use a SocketFactory from our SSLContext
connection.setRequestMethod("POST");
connection.setDoOutput(true);
connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
connection.setConnectTimeout(10000);
connection.setReadTimeout(10000);
PrintWriter out = new PrintWriter(connection.getOutputStream());
out.println(params);
out.close();
BufferedReader in = new BufferedReader(new InputStreamReader(connection.getInputStream()), 8192);
String inputLine;
while ((inputLine = in.readLine()) != null) {
result = result.concat(inputLine);
}
in.close();
//} catch (IOException e) {
} catch (IOException | KeyStoreException | CertificateException | KeyManagementException | NoSuchAlgorithmException e) {
result = e.toString();
e.printStackTrace();
}
return result;
}
回答by threecz
Here's an Android HttpsUrlConnection POST solutioncomplete with certificate pinning, timeouts server side code and configurations.
这是一个带有证书固定、超时服务器端代码和配置的Android HttpsUrlConnection POST 解决方案。
The variable params
should be in the form username=demo&password=abc123&.
该变量params
的格式应为 username=demo&password=abc123&。