在一行中打印一个 int 列表 python3
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Printing an int list in a single line python3
提问by KimioN42
I'm new to python and I'm trying to scan multiple numbers separated by spaces (let's assume '1 2 3' as an example) in a single line and add it to a list of int. I did it by using:
我是 python 的新手，我正在尝试在一行中扫描由空格分隔的多个数字（假设以“1 2 3”为例）并将其添加到 int 列表中。我是通过使用做到的：
#gets the string
string = input('Input numbers: ')
#converts the string into an array of int, excluding the whitespaces
array = [int(s) for s in string.split()]
Apparently it works, since when I type in '1 2 3' and do a print(array)the output is:
显然它有效，因为当我输入“1 2 3”并执行print(array)输出时：
[1, 2, 3]
[1, 2, 3]
But I want to print it in a single line without the brackets, and with a space in between the numbers, like this:
但我想在没有括号的情况下将其打印在一行中，并且数字之间有一个空格，如下所示：
1 2 3
1 2 3
I've tried doing:
我试过这样做：
for i in array:
print(array[i], end=" ")
But I get an error:
但我收到一个错误：
2 3 Traceback (most recent call last):
print(array[i], end=" ")
IndexError: list index out of range
2 3 回溯（最近一次调用最后一次）：
打印（数组[i]，结束=“”）
IndexError：列表索引超出范围
How can I print the list of ints (assuming my first two lines of code are right) in a single line, and without the brackets and commas?
如何在一行中打印整数列表（假设我的前两行代码是正确的），并且没有括号和逗号？
回答by Nikhil Gupta
Yes that is possible in Python 3, just use *before the variable like:
是的，这在Python 3中是可能的，只需*在变量之前使用，例如：
print(*list)
This will print the list separated by spaces.
这将打印由空格分隔的列表。
(where *is the unpackingoperator that turns a list into positional arguments, print(*[1,2,3])is the same as print(1,2,3), see also What does the star operator mean, in a function call?)
（将列表转换为位置参数*的解包运算符在哪里，print(*[1,2,3])与 相同print(1,2,3)，另请参阅函数调用中星号运算符的含义是什么？）
回答by Nick Matteo
You want to say
你想说
for i in array:
print(i, end=" ")
The syntax i in arrayiterates over each member of the list. So, array[i]was trying to access array[1], array[2], and array[3], but the last of these is out of bounds (arrayhas indices 0, 1, and 2).
语法i in array遍历列表的每个成员。因此，array[i]试图访问array[1],array[2]和array[3]，但最后一个超出范围（array索引为 0、1 和 2）。
You can get the same effect with print(" ".join(map(str,array))).
您可以使用 获得相同的效果print(" ".join(map(str,array)))。
回答by Corey Goldberg
these will both work in Python 2.7 and Python 3.x:
这些都适用于 Python 2.7 和 Python 3.x：
>>> l = [1, 2, 3]
>>> print(' '.join(str(x) for x in l))
1 2 3
>>> print(' '.join(map(str, l)))
1 2 3
btw, arrayis a reserved word in Python.
btw，array是 Python 中的保留字。
回答by EoinS
Try using join on a str conversion of your ints:
尝试在 int 的 str 转换上使用 join：
print ' '.join(str(x) for x in array)
回答by 2Cubed
You have multiple options, each with different general use cases.
您有多个选项，每个选项都有不同的一般用例。
The first would be to use a forloop, as you described, but in the following way.
第一种方法是使用for循环，如您所描述的那样，但方式如下。
for value in array:
print(value, end=' ')
You could also use str.joinfor a simple, readable one-liner using comprehension. This method would be good for storing this value to a variable.
您还可以str.join使用理解将其用于简单、可读的单行。这种方法非常适合将此值存储到变量中。
print(' '.join(str(value) for value in array))
My favorite method, however, would be to pass arrayas *args, with a sepof ' '. Note, however, that this method will only produce a printed output, not a value that may be stored to a variable.
然而，我最喜欢的方法是将arrayas传递*args给 a sepof ' '。但是请注意，此方法只会产生printed 输出，而不是可能存储到变量中的值。
print(*array, sep=' ')
回答by Somesh Samadder
# Print In One Line Python
print('Enter Value')
n = int(input())
print(*range(1, n+1), sep="")
回答by mehboob shaikh
If you write
如果你写
a = [1, 2, 3, 4, 5]
print(*a, sep = ',')
You get this output: 1,2,3,4,5
你得到这个输出： 1,2,3,4,5
回答by elad silver
For python 2.7 another trick is:
对于python 2.7，另一个技巧是：
arr = [1,2,3]
for num in arr:
print num,
# will print 1 2 3
