java 在这种情况下如何避免 ArrayIndexOutOfBoundsException？
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How can i avoid ArrayIndexOutOfBoundsException in this case?
提问by ssindelar
Is it possible to avoid ArrayIndexOutOfBoundsException in this case ??
在这种情况下是否可以避免 ArrayIndexOutOfBoundsException ？
package com;
public class Hi {
public static void main(String args[]) {
String[] myFirstStringArray = new String[] { "String 1", "String 2",
"String 3" };
if (myFirstStringArray[3] != null) {
System.out.println("Present");
} else {
System.out.println("Not Present");
}
}
}
回答by ssindelar
Maybe I don't understand the real problem, but what prevents you to check if the index is inside the array before accessing it in this case?
也许我不明白真正的问题，但是在这种情况下，是什么阻止您在访问数组之前检查索引是否在数组内？
if (myIndex < myFirstStringArray.length) {
System.out.println("Present");
} else {
System.out.println("Not Present");
}
回答by user2277872
In arrays, they are measured differently than numbers. The first object inside an array is considered 0. So, in your if statement, instead of a 3, you just put a 2.
在数组中，它们的测量方式与数字不同。数组中的第一个对象被视为 0。因此，在 if 语句中，您只需输入 2，而不是 3。
if (myFirstStringArray[3] != null) {
System.out.println("Present");
to
到
if (myFirstStringArray[2] != null) {
System.out.println("Present");
Hope this helps! :)
希望这可以帮助！:)
回答by Sachin Verma
Your Stringarray contains 3 elements and you are accessing array[3] i.e. 4th element as index in 0 based and so you get this error (Exception, anyway).
您的String数组包含 3 个元素，并且您正在访问数组 [3]，即第 4 个元素作为基于 0 的索引，因此您会收到此错误（无论如何都是异常）。
To avoid the ArrayIndexOutOfBoundsExceptionuse an index within specified index range. And always check whether your index is >=array.length.
避免ArrayIndexOutOfBoundsException使用指定索引范围内的索引。并始终检查您的索引是否为>=array.length.
