Python 使用 xml.etree.ElementTree 获取子节点的所有实例
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Getting all instances of child node using xml.etree.ElementTree
提问by Ash
I have the following XML file as input:
我有以下 XML 文件作为输入：
<Test>
<callEvents>
<moc>
<causeForTermination>0</causeForTermination>
<serviceCode>
<teleServiceCode>11</teleServiceCode>
</serviceCode>
<dialledDigits>5555555</dialledDigits>
<connectedNumber>77777</connectedNumber>
</moc>
<moc>
<causeForTermination>0</causeForTermination>
<serviceCode>
<teleServiceCode>11</teleServiceCode>
</serviceCode>
<dialledDigits>2222222</dialledDigits>
</moc>
</callEvents>
<callEventsCount>100</callEventsCount>
</Test>
I want to output all the values for dialledDigits. However, my code only displays the first instance of dialledDigits.
我想输出 dialledDigits 的所有值。但是，我的代码只显示了 dialledDigits 的第一个实例。
dialledDigits {} 5555555
My desired output should contain both instances.
我想要的输出应该包含这两个实例。
dialledDigits {} 5555555
dialledDigits {} 2222222
Here is my code
这是我的代码
import xml.etree.ElementTree as ET
tree = ET.parse('as.xml')
root = tree.getroot()
callevent=root.find('callEvents')
Moc1=callevent.find('moc')
for node in Moc1.getiterator():
if node.tag=='dialledDigits':
print node.tag, node.attrib, node.text
采纳答案by Celeo
回答by Vivek Sable
find()will return first tag object, so use finadall()which return all tag objects`
find()将返回第一个标签对象，所以使用finadall()它返回所有标签对象`
>>> Moc1=callevent.find('moc')
>>> Moc1
<Element 'moc' at 0x869a2ac>
>>> Moc1=callevent.findall('moc')
>>> Moc1
[<Element 'moc' at 0x869a2ac>, <Element 'moc' at 0x869a4ec>]
>>>
Iterate on it:
迭代它：
>>> Mocs=callevent.findall('moc')
>>> for moc in Mocs:
... for node in moc.getiterator():
... if node.tag=='dialledDigits':
... print node.tag, node.attrib, node.text
...
dialledDigits {} 5555555
dialledDigits {} 2222222
回答by alecxe
You can also write an XPath expression. Just 2 lines instead of 5 and a single loop:
您还可以编写XPath 表达式。只有 2 行而不是 5 行和一个循环：
for node in tree.findall('.//callEvents/moc/dialledDigits'):
print node.tag, node.attrib, node.text
Demo:
演示：
>>> import xml.etree.ElementTree as ET
>>>
>>>
>>> tree = ET.parse('as.xml')
>>> root = tree.getroot()
>>>
>>> for node in tree.findall('.//callEvents/moc/dialledDigits'):
... print node.tag, node.attrib, node.text
...
dialledDigits {} 5555555
dialledDigits {} 2222222
