php 如何在mysql数据库连接中使用抛出异常
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/9836693/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
how to use throw exception in mysql database connect
提问by Django Anonymous
I come across this:-
我遇到了这个:-
PHP Error handling: die() Vs trigger_error() Vs throw Exception
PHP 错误处理:die() Vs trigger_error() Vs throw Exception
and understood that throw exception is better
并理解抛出异常更好
How can i replace die and use throw exception here in this code:-
我如何在此代码中替换 die 并在此处使用 throw 异常:-
<?php
# FileName="Connection_php_mysql.htm"
# Type="MYSQL"
# HTTP="true"
$hostname_db = "localhost";
$database_db = "database";
$username_db = "root";
$password_db = "password";
$db = mysqli_connect($hostname_db, $username_db, $password_db) or die("Unable to connect with Database");
?>
回答by slash197
try
{
if ($db = mysqli_connect($hostname_db, $username_db, $password_db))
{
//do something
}
else
{
throw new Exception('Unable to connect');
}
}
catch(Exception $e)
{
echo $e->getMessage();
}
回答by burzum
It is documented here http://ie2.php.net/manual/en/mysqli.error.php
它记录在这里http://ie2.php.net/manual/en/mysqli.error.php
if (mysqli_connect_errno()) {
throw new RuntimeException("Connect failed: %s\n", mysqli_connect_error());
}