php 如何将 getimagesize() 与 $_FILES[''] 一起使用?
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/9799343/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
How can I use getimagesize() with $_FILES['']?
提问by eric01
I am doing an image upload handler and I would like it to detect the dimensions of the image that's been uploaded by the user.
我正在做一个图像上传处理程序,我希望它检测用户上传的图像的尺寸。
So I start with:
所以我开始:
if (isset($_FILES['image'])) etc....
and I have
我有
list($width, $height) = getimagesize(...);
How am i supposed to use them together?
我应该如何一起使用它们?
Thanks a lot
非常感谢
回答by Starx
You can do this as such
你可以这样做
$filename = $_FILES['image']['tmp_name'];
$size = getimagesize($filename);
// or
list($width, $height) = getimagesize($filename);
// USAGE: echo $width; echo $height;
Using the condition combined, here is an example
使用条件组合,这里是一个例子
if (isset($_FILES['image'])) {
$filename = $_FILES['image']['tmp_name'];
list($width, $height) = getimagesize($filename);
echo $width;
echo $height;
}
回答by Khurram Ijaz
from php manual very simple example.
来自php手册非常简单的例子。
list($width, $height, $type, $attr) = getimagesize("img/flag.jpg");
echo "<img src=\"img/flag.jpg\" $attr alt=\"getimagesize() example\" />";
回答by Andreas Wong
list($w, $h) = getimagesize($_FILES['image']['tmp_name']);
From the docs:
从文档:
Index 0 and 1 contains respectively the width and the height of the image.
Index 2 is one of the IMAGETYPE_XXX constants indicating the type of the image.
Index 3 is a text string with the correct height="yyy" width="xxx" string that can be used directly in an IMG tag.
索引 0 和 1 分别包含图像的宽度和高度。
索引 2 是指示图像类型的 IMAGETYPE_XXX 常量之一。
索引 3 是具有正确 height="yyy" width="xxx" 字符串的文本字符串,可以直接在 IMG 标签中使用。
So you can just do list() and don't worry about indexes, it should get the info you need :)
所以你可以只做 list() 而不用担心索引,它应该得到你需要的信息:)
回答by Sulung Nugroho
Try this for multi images :
试试这个多图像:
for($i=0; $i < count($filenames); $i++){
$image_info = getimagesize($images['tmp_name'][$i]);
$image_width = $image_info[0];
$image_height = $image_info[1];
}
Try this for single image :
对单个图像试试这个:
$image_info = getimagesize($images['tmp_name']);
$image_width = $image_info[0];
$image_height = $image_info[1];
at least it works for me.
至少它对我有用。