C++ “ofstream”作为函数参数
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"ofstream" as function argument
提问by Shibli
Is there a way to pass output stream as argument like
有没有办法将输出流作为参数传递
void foo (std::ofstream dumFile) {}
void foo (std::ofstream dumFile) {}
I tried that but it gave
我试过了,但它给了
error : class "std::basic_ofstream<char, std::char_traits<char>>" has no suitable copy constructor
error : class "std::basic_ofstream<char, std::char_traits<char>>" has no suitable copy constructor
回答by Boris Strandjev
Of course there is. Just use reference. Like that:
当然有。只用参考。像那样:
void foo (std::ofstream& dumFile) {}
Otherwise the copy constructor will be invoked, but there is no such defined for the class ofstream
.
否则将调用复制构造函数,但没有为 class 定义这样的构造函数ofstream
。
回答by Joel Falcou
You have to pass a reference to the ostream
object as it has no copy constructor:
您必须传递对该ostream
对象的引用,因为它没有复制构造函数:
void foo (std::ostream& dumFile) {}
回答by Mankarse
If you are using a C++11 conformant compiler and standard library, it should be ok to use
如果您使用的是符合 C++11 的编译器和标准库,则应该可以使用
void foo(std::ofstream dumFile) {}
as long as it is called with an rvalue. (Such calls will look like foo(std::ofstream("dummy.txt"))
, or foo(std::move(someFileStream))
).
只要它是用右值调用的。(这样的调用看起来像foo(std::ofstream("dummy.txt"))
, 或foo(std::move(someFileStream))
)。
Otherwise, change the parameter to be passed by reference, and avoid the need to copy/move the argument:
否则,更改为通过引用传递的参数,并避免需要复制/移动参数:
void foo(std::ofstream& dumFile) {}