Java - 按步骤对任何数组进行切片
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Java - Slice any array at steps
提问by robman
In python we are able to do the following:
在python中，我们能够执行以下操作：
array = [0,1,2,3,4,5,6,7,8,9,10]
new_array= array[::3]
print(new_array)
>>>[0,3,6,9]
Is there an equivalent to this in Java? I have been looking for this type of array slicing, but I have had no luck. Any help would be great, Thanks!
在 Java 中有与此等效的吗？我一直在寻找这种类型的数组切片，但我没有运气。任何帮助都会很棒，谢谢！
回答by Michael Markidis
If you are using Java 8, then you can make use of streams and do the following:
如果您使用的是 Java 8，那么您可以使用流并执行以下操作：
int [] a = new int [] {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
// filter out all indices that evenly divide 3
int [] sliceArr = IntStream.range(0, a.length).filter(i -> i % 3 == 0)
.map(i -> a[i]).toArray();
System.out.println(Arrays.toString(sliceArr));
Outputs: [0, 3, 6, 9]
输出：[0, 3, 6, 9]
回答by gbtimmon
There is a method in Arrays that might help.
Arrays 中有一种方法可能会有所帮助。
int[] newArr = Arrays.copyOfRange(arr, 5,10);
It is obviously far less powerful the the python implementation.
显然，python 实现的功能要弱得多。
回答by Ironcache
Java has no built-in mechanism for this. You could write a helper function:
Java 没有为此提供内置机制。你可以写一个辅助函数：
public static int[] sliceArray(int[] arr, int spacing) {
int curr = 0;
int[] newArr = new int[((arr.length - 1) / spacing) + 1];
for (int i = 0; i < newArr.length; ++i) {
newArr[i] = arr[curr];
curr += spacing;
}
return newArr;
}
Note that Michael's answer is better (or at least less verbose) if you can utilize Java 8.
请注意，如果您可以使用 Java 8，Michael 的回答会更好（或至少不那么冗长）。
