C++:: 使用向量迭代器调用类方法？
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C++:: Call class method using vector iterator?
提问by cpp_noob
I have a class called Room, the Room class has setPrice and display function.
我有一个名为 Room 的类，Room 类具有 setPrice 和 display 功能。
I stored room objects in a vector:
我将房间对象存储在向量中：
room.push_back(Room("r001", 1004, 2, "small"));
room.push_back(Room("r002", 1005, 2, "small"));
room.push_back(Room("r003", 2001, 4, "small"));
room.push_back(Room("r004", 2002, 4, "small"));
In my main function, i create a display function to display all rooms. Here is my code:
在我的主要功能中，我创建了一个显示功能来显示所有房间。这是我的代码：
void displayRoom()
{
vector<Room>::iterator it;
for (it = room.begin(); it != room.end(); ++it) {
*it.display(); // just trying my luck to see if it works
}
}
But it does not call the Room's display method.
但它不会调用 Room 的显示方法。
How do I call the Room(class)'s display method (no argument) and setPrice(1 argument) method?
如何调用 Room(class) 的显示方法（无参数）和 setPrice(1 参数) 方法？
回答by
Dereferencing has higher priority than member access. You could add parens ((*it).display()), but you should just use the shortcut that was introduced long long ago (in C) for this: it->display().
解除引用比成员访问具有更高的优先级。你可以添加括号（(*it).display()），但你应该使用被引入很久很久以前（在C）的快捷方式是：it->display()。
Of course the same rule applies for pointers and everything else that can be dereferenced (other iterators, smart pointers, etc.).
当然，同样的规则适用于指针和其他所有可以取消引用的东西（其他迭代器、智能指针等）。
回答by Alexandre C.
Try (*it).display()or simply it->display().
尝试(*it).display()或干脆it->display()。
回答by Oliver Charlesworth
Iterators are a bit like pointers. So you want either:
迭代器有点像指针。所以你想要：
it->display();
or:
或者：
(*it).display();
回答by Oliver Charlesworth
Using Vector, you can also use classic form
使用 Vector，您还可以使用经典形式
for(size_t x = 0; x < room.size(); x++) {
room[x].display(); //for objects
//room[x]->display(); //for pointers
}
