“int”对象在python中不可调用错误
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时间：2020-08-18 19:41:03 来源:igfitidea点击:
'int' object is not callable error in python
提问by GeorgeDavidKing
I'm getting this error:
我收到此错误：
Traceback (most recent call last):
File "C:\Users\George\Desktop\ex3.py", line 15, in <module>
s=s+d*2(-1/6.)*(u-1)*(u-2)*(u+2)*(u-4)
TypeError: 'int' object is not callable
Here is my code:
这是我的代码：
x=input()
z=input()
n=input()
while x>=z:
x=input()
z=input()
while n<0:
n=input()
while n>0:
d=(z-x)/1.*n
k=1
s=(d/2.)*((-1/6.)*(x-1)*(x-2)*(x+2)*(x-4)+(-1/6.)*(z-1)*(z-2)*(z+2)*(z-4))
while k<=n-1:
u=x+k*d
s=s+d*2(-1/6.)*(u-1)*(u-2)*(u+2)*(u-4)
k=k+1
print "%.3f" %s
x=input()
z=input()
n=input()
if n>0:
while x>=z:
x=input()
z=input()
采纳答案by Martijn Pieters
You are trying to use 2as a function:
您正在尝试2用作函数：
2(-1/6.)
Insert a *to multiply:
插入一个*乘法：
2*(-1/6.)
or as a full expression:
或者作为一个完整的表达：
s=s+d*2*(-1/6.)*(u-1)*(u-2)*(u+2)*(u-4)
