php SQL 查询中的数组?

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时间:2020-08-25 20:53:58  来源:igfitidea点击:

Array in SQL Query?

phpmysql

提问by njaknjak

i have a problem making a SQL Query with an array in my WHERE clause.

我在 WHERE 子句中使用数组进行 SQL 查询时遇到问题。

For example:

例如:

My Array:

我的阵列:

$myarray[1] = "hi";
$myarray[2] = "there";
$myarray[3] = "everybody";

My MySQL Statement:

我的 MySQL 声明:

SELECT * FROM myTable WHERE title='".$myarray[]."'

Is there any way to realize that? I solved it myself like this:

有没有办法意识到这一点?我自己是这样解决的:

for(...) {
$where = $where." title='".$myarray[$count]."' OR ";
}
$where = substr($where , 0, -3);
.....
SELECT * FROM myTable WHERE ".$where."

But if i had thousands of entries in my array, the SQL Statement would be too big and slow, right?

但是如果我的数组中有数千个条目,那么 SQL 语句就会太大太慢,对吗?

Thanks

谢谢

回答by Tim

You can use mysql's IN-function

你可以使用mysql的IN函数

EDIT: As amosrevira said, you need to escape you strings in the array.

编辑:正如 amosrevira 所说,您需要对数组中的字符串进行转义。

$myarray[1] = "'hi'";
$myarray[2] = "'there'";
$myarray[3] = "'everybody'";

$newarray = implode(", ", $myarray); //makes format 'hi', 'there', 'everybody' 

SELECT * FROM myTable WHERE title IN ($newarray);

回答by Your Common Sense

$myarray[1] = "hi";
$myarray[2] = "there";
$myarray[3] = "everybody";

//every quoted string should be escaped according to SQL rules
foreach($myarray as $key => $val) {
  $myarray[$key] = mysql_real_escape_string($val);
}

$in_str = "'".implode("', '", $myarray)."'"; //makes format 'hi', 'there', 'everybody' 

SELECT * FROM myTable WHERE title IN ($in_str);

回答by Hamish

You can us the INoperator. You want it to look like:

您可以联系我们的IN运营商。你希望它看起来像:

title IN ('hi', 'there', 'everybody')

So you'd do something like:

所以你会做这样的事情:

$sql = "SELECT * FROM myTable WHERE title IN '" . implode("','", $myarray) . "';"

Note that you need to filter your array for SQL injection issues first.

请注意,您需要首先针对 SQL 注入问题过滤数组。

回答by Muthu Kumaran

You can try use of INin your WHEREclause,

你可以尝试IN在你的WHERE条款中使用,

SELECT * FROM myTable WHERE title IN ('hi', 'there', 'everybody');

or

或者

SELECT * FROM myTable WHERE title IN ('.implode(',', $myarray).');