php Laravel 5 输入旧为空
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Laravel 5 input old is empty
提问by balkondemiri
My routes is here
我的路线在这里
Route::get('sign-up', ['as' => 'signUp', 'uses' => 'UserController@signUpGet']);
Route::post('sign-up', ['as' => 'signUpPost', 'uses' => 'UserController@signUpPost']);
Controller
控制器
return redirect('signUp')->withInput();
And View
并查看
<form role="form" method="POST" action="{{route('signUpPost')}}">
<input type="text" class="form-control" name="username" value="{{ old('username') }}">
</form>
The {{old()}} function return empty value.
EDIT
I took
{{old()}} 函数返回空值。
编辑
我拿了
NotFoundHttpException in RouteCollection.php line 145:
回答by Laurence
Your problem looks like you are not actually submitting the username in the first place:
您的问题看起来您实际上并没有首先提交用户名：
<form role="form" method="POST" action="{{route('signUpPost')}}">
<input type="text" class="form-control" name="username" value="{{ old('username') }}">
</form>
There is no 'submit' button inside the form. If you submit outside the form - then the usernamewill not be included.
表单内没有“提交”按钮。如果您在表单之外提交 - 那么username将不包括在内。
Add the submit button inside your form - then try again
在表单中添加提交按钮 - 然后再试一次
<form role="form" method="POST" action="{{route('signUpPost')}}">
<input type="text" class="form-control" name="username" value="{{ old('username') }}">
<input type="submit" value="Submit">
</form>
Edit - also your controller is wrong. It should be this:
编辑 - 您的控制器也是错误的。应该是这样的：
return redirect()->route('signUp')->withInput();
回答by Alejandro
All you are missing is to Flash the Input to the session. This is so it's available during the next request.
您所缺少的只是将输入闪存到会话中。这样它在下一个请求期间可用。
$request->flash();
Do that just before calling to View your form.
在调用查看表单之前执行此操作。
回答by Anonymouse
You can try this: {{ Input::old('username') }}.
你可以试试这个：{{ Input::old('username') }}。
回答by AlmostPitt
I realize this isn't the case in this particular situation, but I ran into this problem as well. My problem here was caused by "data-prefill" in the input. Once I removed this, it worked.
我意识到在这种特殊情况下情况并非如此，但我也遇到了这个问题。我的问题是由输入中的“数据预填充”引起的。一旦我删除了它，它就起作用了。
Good luck everyone!
大家好运！
回答by yadu
<div class="form-group @if($errors->first('username')) has-error @endif">
<label for="username" class="rtl">Enter user name </label>
<input type="text" name="username" class="form-control rtl basic-usage" id="username" placeholder="Enter user name" value="{!! old('username') !!}">
<span class="help-block required">{{$errors->first('username')}}</span>
</div>
above form field will show old value entered. will show validation error (you have to specify error separately.) have a place holder. bootstrap to look better.(add bootstrap)
上面的表单字段将显示输入的旧值。将显示验证错误（您必须单独指定错误。）有一个占位符。引导程序看起来更好。（添加引导程序）
