php 如何从php中的字符串中删除括号？
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How to remove brackets from string in php?
提问by hairynuggets
I have the following string and would like to use str_replace or preg_replace to remove the brackets but am unsure how. I have been able to remove the opening brackets using str_replace but can't remove the closing brackets.
我有以下字符串，想使用 str_replace 或 preg_replace 删除括号，但我不确定如何。我已经能够使用 str_replace 删除左括号，但无法删除右括号。
This is the sting:
这是刺痛：
$coords = '(51.50972493425563, -0.1323877295303646)';
I have tried:
我试过了：
<?php echo str_replace('(','',$coords); ?>
which removed the opening brackets but am now under the impression that I need preg_replace to remove both.
它删除了左括号，但现在的印象是我需要 preg_replace 来删除两者。
How does one go about this?
如何解决这个问题？
Help appreciated
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回答by hsz
Try with:
尝试：
str_replace(array( '(', ')' ), '', $coords);
回答by Sarfraz
回答by symcbean
echo str_replace(
array('(',')'), array('',''),
$coords);
or just do str_replace twice....
或者只是做 str_replace 两次....
echo str_replace(')', '', str_replace('(','',$coords));
回答by rauschen
it is easier than you think, str_replace can have an array as first parameter
这比你想象的要容易，str_replace 可以有一个数组作为第一个参数
<?php echo str_replace(array('(',')'),'',$coords); ?>
回答by Stefan Koenen
i think you need to write your coords here as a string else you get syntax error ;). Anyway, this is the solution i think.
我认为你需要在这里写你的坐标作为一个字符串，否则你会得到语法错误；)。无论如何，这是我认为的解决方案。
$coords = "(51.50972493425563, -0.1323877295303646)";
$aReplace = array('(', ')');
$coordsReplaced = str_replace($aReplace , '', $coords);
Greets, Stefan
问候，斯蒂芬
