将带有通配符 (*) 的文件复制到 bash 脚本中的文件夹 - 为什么它不起作用?
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/21924351/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Copying files with wildcard (*) to a folder in a bash script - why isn't it working?
提问by boltup_im_coding
I am writing a bash script that creates a folder, and copies files to that folder. It works from the command line, but not from my script. What is wrong here?
我正在编写一个 bash 脚本来创建一个文件夹,并将文件复制到该文件夹中。它可以从命令行运行,但不能从我的脚本运行。这里有什么问题?
#! /bin/sh
DIR_NAME=files
ROOT=..
FOOD_DIR=food
FRUITS_DIR=fruits
rm -rf $DIR_NAME
mkdir $DIR_NAME
chmod 755 $DIR_NAME
cp $ROOT/$FOOD_DIR/"*" $DIR_NAME/
I get:
我得到:
cp: cannot stat `../food/fruits/*': No such file or directory
回答by Charles Duffy
You got that exactly backwards -- everything exceptthe *
character should be double-quoted:
你完全倒退了——除了*
字符之外的所有东西都应该用双引号引起来:
#!/bin/sh
dir_name=files
root=..
food_dir=food
fruits_dir=fruits
rm -rf "$dir_name"
mkdir "$dir_name"
chmod 755 "$dir_name"
cp "$root/$food_dir/"* "$dir_name/"
Also, as a matter of best-practice / convention, non-environment variable names should be lower case to avoid name conflicts with environment variables and builtins.
此外,作为最佳实践/约定的问题,非环境变量名称应小写,以避免与环境变量和内置变量的名称冲突。