bash 在linux bash中将ISO日期转换为自纪元以来的秒数
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Convert an ISO date to seconds since epoch in linux bash
提问by Gianluca Ghettini
I have a date in the ISO format YYYY-MM-DDTHH:SS (e.g. 2014-02-14T12:30). I'd like to convert it in seconds since epoch using only the date command in linux bash.
我有一个 ISO 格式的日期 YYYY-MM-DDTHH:SS（例如 2014-02-14T12:30）。我想在 linux bash 中仅使用 date 命令在几秒钟内转换它。
All the dates refer to UTC locale.
所有日期均指 UTC 语言环境。
I know that this question is easily eligible for duplicate... there are billions of questions about converting dates from one format to another but I can't find my particular scenario
我知道这个问题很容易重复......关于将日期从一种格式转换为另一种格式的问题有数十亿，但我找不到我的特定场景
thank you...
谢谢你...
回答by kguest
With GNU date, specify the date to parse with -dand seconds since epoch with %s
使用 GNU 日期，指定要解析的日期-d和自纪元以来的秒数%s
$ date -d"2014-02-14T12:30" +%s
1392381000
回答by Mohammed Rafeeq
It is easier if you install gdateto deal with date strings that have timezones with nano second precision
如果您安装gdate处理具有纳秒精度的时区的日期字符串会更容易
install coreutilsand you will get gdatealong
install coreutils你会相处得gdate很好
on mac brew install coreutils
在 Mac 上 brew install coreutils
gdate --date="2010-10-02T09:35:58.203Z" +%s%N
This is particularly useful when inserting the time series value into influxdb
这在将时间序列值插入 influxdb 时特别有用
in a shell script variable = $(gdate --date="2010-10-02T09:35:58.203Z" +%s%N)
在 shell 脚本中 variable = $(gdate --date="2010-10-02T09:35:58.203Z" +%s%N)
echo $variable
