Python Pygame 图像位置
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Pygame Image position
提问by user2993584
I've recentley started using pygame to see what I could come up with and come across a problem which I can't find an answer to without this pygame.sprite.Sprite and rect things, my question is how do I find a position of an image since I need the position of it to calculate a rotation angle. If it helps, here's the code that i am using:
我最近开始使用 pygame 来看看我能想出什么并遇到一个问题，如果没有这个 pygame.sprite.Sprite 和 rect 的东西我就找不到答案，我的问题是我如何找到一个位置一个图像，因为我需要它的位置来计算旋转角度。如果有帮助，这是我正在使用的代码：
import sys, pygame, math, time;
from pygame.locals import *;
spaceship = ('spaceship.png')
mouse_c = ('crosshair.png')
backg = ('background.jpg')
fire_beam = ('beam.png')
pygame.init()
screen = pygame.display.set_mode((800, 600))
bk = pygame.image.load(backg).convert_alpha()
mousec = pygame.image.load(mouse_c).convert_alpha()
space_ship = pygame.image.load(spaceship).convert_alpha()
f_beam = pygame.image.load(fire_beam).convert_alpha()
clock = pygame.time.Clock()
pygame.mouse.set_visible(False)
space_ship_rect = space_ship.get_rect() #added
while True:
screen.blit(bk, (0, 0))
for event in pygame.event.get():
if event.type == QUIT:
pygame.quit()
sys.exit()
elif event.type == MOUSEBUTTONDOWN and event.button == 1:
print("Left Button Pressed")
elif event.type == MOUSEBUTTONDOWN and event.button == 3:
print("Right Button Pressed")
if event.type == MOUSEMOTION:
x1, y1 = pygame.mouse.get_pos()
x2, y2 = space_ship_rect.x, space_ship_rect.y #added
dx, dy = x2 - x1, y2 - y1
rads = math.atan2(dx, dy)
degs = math.degrees(rads)
print degs
pygame.transform.rotate(space_ship, degs)
pygame.display.update()
pos = pygame.mouse.get_pos()
screen.blit(mousec, (pos))
#screen.blit(space_ship, (375, 300)) #space_ship_rect did not work here.
pygame.display.update()
采纳答案by furas
You can use .get_rect()for image to get image rectangle (pygame.Rect())
您可以使用.get_rect()for image 来获取图像矩形 ( pygame.Rect())
space_ship = pygame.image.load(spaceship).convert_alpha()
space_ship_rect = space_ship.get_rect()
and than you can get x, y, width, heightand even centerx, centery, centeretc.
比你可以得到x，y，width，height甚至centerx，centery，center等。
print space_ship_rect.x, space_ship_rect.y,
print space_ship_rect.centerx, space_ship_rect.centery,
print space_ship_rect.center
print space_ship_rect.left, space_ship_rect.right
print space_ship_rect.top, space_ship_rect.bottom
print space_ship_rect.topleft, space_ship_rect.bottomright
print space_ship_rect.width, space_ship_rect.height
by the way: .get_rect()works also with your screenand other pygame.Surface().
顺便说一句：.get_rect()也适用于您screen和其他人pygame.Surface()。
But you can't assign new values to image so you have to keep space_ship_rectand change values in it (so use get_rect()only once to get image size)
但是您不能为图像分配新值，因此您必须保留space_ship_rect和更改其中的值（因此get_rect()只能使用一次来获取图像大小）
space_ship_rect.x = 100
space_ship_rect.y = 200
# or
space_ship_rect.centerx = 100
space_ship_rect.centery = 200
If you change x, yrectangle recalculate centerx, centeryusing widthand height. If you change centerx, centeryrectangle recalculate xand y
如果更改x，y矩形重新计算centerx，centery使用width和height。如果您更改centerx，则centery矩形重新计算x并y
You could create class with self.imagefor bitmap and self.rectfor image size and position.
您可以self.image为位图以及self.rect图像大小和位置创建类。
ps. you can use screen.blit(space_ship, space_ship_rect)
附：您可以使用screen.blit(space_ship, space_ship_rect)
