Python 类型错误：不支持 ^ 的操作数类型：'float' 和 'int'
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Python TypeError: unsupported operand type(s) for ^: 'float' and 'int'
提问by Aris Pap
I wrote a simple program which approximates the evaluation of a definite integral using numerical integration. However, I am stumped when it comes to why I am getting the error in the title. Keep in mind that I haven't touched python in one and a half years so it might be something incredibly obvious that I'm missing, however I'd still be grateful if you could help me :) Here is the code:
我写了一个简单的程序，它使用数值积分来近似计算定积分。但是，当谈到为什么我在标题中收到错误时，我很难过。请记住，我已经有一年半没有接触过 python 了，所以我遗漏了一些非常明显的东西，但是如果你能帮助我，我仍然会很感激:) 这是代码：
import math
def f(x):
f=math.sqrt(1+(6*x+4)^2)
return f
lbound=int(input("Input lower bound for the integral"))
ubound=int(input("Input upper bound for the integral"))
n=int(input("Input number of intervals"))
dx=((ubound-lbound)/n)
integral=0
for i in range(1,n):
integral=integral+dx*f(i*dx)
print (integral)
Here is the full error report IDLE gives me when trying to run the code:
这是 IDLE 在尝试运行代码时给我的完整错误报告：
Traceback (most recent call last):
File "C:\Users\******\Desktop\integrals.py", line 13, in <module>
integral=integral+dx*f(n*dx)
File "C:\Users\******\Desktop\integrals.py", line 3, in f
f=math.sqrt(1+(6*x+4)^2)
TypeError: unsupported operand type(s) for ^: 'float' and 'int'
采纳答案by ilyas patanam
When trying to raise to a power use the operand use **and not ^.
当试图提高到权力使用操作数使用**而不是^.
f=math.sqrt(1+(6*x+4)**2)
