创建一个 PHP 类 -> 在另一个类中创建它的对象
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Create a PHP Class -> Create an object of it in another class
提问by user277813
I have created a PHP class called formChecker.php. It validates a form. As a Java programmer, I would like to stick with the idea of creating an instance of this class in another class and run it from there. It doesn't seem to be working for me.The following is a demonstration:
我创建了一个名为 formChecker.php 的 PHP 类。它验证表单。作为一名 Java 程序员，我想坚持在另一个类中创建此类的实例并从那里运行它的想法。它似乎对我不起作用。以下是演示：
class formChecker{
..... validation functions go here
}
class runFormChecker{
.... create instance of formchecker here and use it's methods etc.
}
Can this be done? What I'm thinking of is developing a number of classes that can be run seperately.
这能做到吗？我在想的是开发一些可以单独运行的类。
GF
GF
回答by Sarfraz
Just include the formCheckerclass file just before the class you want to use it in eg:
只需formChecker在要使用它的类之前包含类文件，例如：
include "formChecker.php"
class runFormChecker{
function __construct() {
$obj = new formChecker; // create instance
// more processing............
}
}
If however, you have both classes in one file (which is bad), then no need to include the file, you can create the instance of that straight away eg:
但是，如果您在一个文件中拥有两个类（这很糟糕），则无需包含该文件，您可以立即创建该文件的实例，例如：
class formChecker{
// ............
}
class runFormChecker{
function __construct() {
$obj = new formChecker; // create instance
// more processing............
}
}
Thanks :)
谢谢 ：）
回答by VolkerK
I'd rather pass the instance of formChecker (or something that implements a certain interface) to the instance of runFormChecker. see http://en.wikipedia.org/wiki/Dependency_injection
我宁愿将 formChecker 的实例（或实现某个接口的东西）传递给 runFormChecker 的实例。见http://en.wikipedia.org/wiki/Dependency_injection
Could be as simple as
可能很简单
interface FormChecker {
public function foo($x);
}
class MyFormChecker implements FormChecker
public function foo($x) {
return true;
}
}
class RunFormChecker {
protected $formChecker=null;
public function __construct(FormChecker $fc) {
$this->formChecker = $fc;
}
// ....
}
$rfc = new RunFormChecker(new MyFormChecker);
回答by Ignacio Vazquez-Abrams
Yes, and this is not strange. You would usually create the instance of formCheckerwithin an instance of runFormCheckerthough, and not at the class level.
是的，这并不奇怪。你通常会创建的实例formChecker的实例中runFormChecker的一流水平，虽然，没有。
