我的简单python程序不断收到此错误：“TypeError：'float'对象不能解释为整数”
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I keep getting this error for my simple python program: "TypeError: 'float' object cannot be interpreted as an integer"
提问by remorath
I don't understand why I can't use my variable c.
我不明白为什么我不能使用我的变量c。
code:
代码：
from turtle import *
speed(0)
hideturtle()
c = 450
def grid(x,y,a):
seth(0)
pu()
goto(x,y)
pd()
for i in range(4):
forward(a)
rt(90)
for i in range(c/10):
seth(0)
forward(10)
rt(90)
forward(c)
backward(c)
for i in range(c/10):
seth(0)
rt(90)
forward(10)
rt(90)
forward(c)
backward(c)
pu()
goto(a+10,0)
write("x")
goto(0,a+10)
write("y")
pd()
grid(0,0,c)
grid(-c,0,c)
grid(-c,c,c)
grid(0,c,c)
I get the following error message:
我收到以下错误消息：
Traceback (most recent call last):
File "C:\Users\nick\Desktop\gridv2.py", line 35, in <module>
grid(0,0,c)
File "C:\Users\nick\Desktop\gridv2.py", line 15, in grid
for i in range(c/10):
TypeError: 'float' object cannot be interpreted as an integer
采纳答案by Jon Clements
In:
在：
for i in range(c/10):
You're creating a float as a result - to fix this use the int division operator:
因此，您正在创建一个浮点数 - 要解决此问题，请使用 int 除法运算符：
for i in range(c // 10):
回答by Martijn Pieters
range()can only work with integers, but dividing with the /operator always results in a float value:
range()只能处理整数，但与/运算符相除总是会产生浮点值：
>>> 450 / 10
45.0
>>> range(450 / 10)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'float' object cannot be interpreted as an integer
Make the value an integer again:
再次将该值设为整数：
for i in range(int(c / 10)):
or use the //floor division operator:
或使用//楼层除法运算符：
for i in range(c // 10):
回答by Jon Clements
As shown below, rangeonly supports integers:
如下图，range只支持整数：
>>> range(15.0)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: range() integer end argument expected, got float.
>>> range(15)
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14]
>>>
However, c/10is a float because /always returns a float.
然而，c/10是一个浮点数，因为/总是返回一个浮点数。
Before you put it in range, you need to make c/10an integer. This can be done by putting it in int:
在你把它放进去之前range，你需要做c/10一个整数。这可以通过将其放入来完成int：
range(int(c/10))
or by using //, which returns an integer:
或通过 using //，它返回一个整数：
range(c//10)
