C++ 使用基于范围的 for 循环时需要迭代器

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时间:2020-08-28 21:00:59  来源:igfitidea点击:

Need iterator when using ranged-based for loops

c++c++11for-loopiterator

提问by u359653

Currently, I can only do ranged based loops with this:

目前,我只能用这个做基于范围的循环:

for (auto& value : values)

But sometimes I need an iterator to the value, instead of a reference (For whatever reason). Is there any method without having to go through the whole vector comparing values?

但有时我需要一个值的迭代器,而不是一个引用(无论出于何种原因)。有没有什么方法不需要通过整个向量比较值?

采纳答案by Nawaz

Use the old forloop as:

使用旧for循环作为:

for (auto it = values.begin(); it != values.end();  ++it )
{
       auto & value = *it;
       //...
}

With this, you've valueas well as iterator it. Use whatever you want to use.

有了这个,你value和 iterator 一样it。想用什么就用什么。



EDIT:

编辑:

Although I wouldn't recommended this, but if you want to use range-based forloop (yeah, For whatever reason:D), then you can do this:

虽然我不推荐这样做,但是如果您想使用基于范围的for循环(是的,无论出于何种原因:D),那么您可以这样做:

 auto it = std::begin(values); //std::begin is a free function in C++11
 for (auto& value : values)
 {
     //Use value or it - whatever you need!
     //...
     ++it; //at the end OR make sure you do this in each iteration
 }

This approach avoids searching given value, since valueand itare always in sync.

这种方法避免了搜索 given value,因为valueit总是同步的。

回答by Potatoswatter

Here is a proxy wrapper class to allow you to expose the hidden iterator by aliasing it to your own variable.

这是一个代理包装器类,允许您通过将其别名为您自己的变量来公开隐藏的迭代器。

#include <memory>
#include <iterator>

/*  Only provides the bare minimum to support range-based for loops.
    Since the internal iterator of a range-based for is inaccessible,
    there is no point in more functionality here. */
template< typename iter >
struct range_iterator_reference_wrapper
    : std::reference_wrapper< iter > {
    iter &operator++() { return ++ this->get(); }
    decltype( * std::declval< iter >() ) operator*() { return * this->get(); }
    range_iterator_reference_wrapper( iter &in )
        : std::reference_wrapper< iter >( in ) {}
    friend bool operator!= ( range_iterator_reference_wrapper const &l,
                             range_iterator_reference_wrapper const &r )
        { return l.get() != r.get(); }
};

namespace unpolluted {
    /*  Cannot call unqualified free functions begin() and end() from 
        within a class with members begin() and end() without this hack. */
    template< typename u >
    auto b( u &c ) -> decltype( begin( c ) ) { return begin( c ); }
    template< typename u >
    auto e( u &c ) -> decltype( end( c ) ) { return end( c ); }
}

template< typename iter >
struct range_proxy {
    range_proxy( iter &in_first, iter in_last )
        : first( in_first ), last( in_last ) {}

    template< typename T >
    range_proxy( iter &out_first, T &in_container )
        : first( out_first ),
        last( unpolluted::e( in_container ) ) {
        out_first = unpolluted::b( in_container );
    }

    range_iterator_reference_wrapper< iter > begin() const
        { return first; }
    range_iterator_reference_wrapper< iter > end()
        { return last; }

    iter &first;
    iter last;
};

template< typename iter >
range_proxy< iter > visible_range( iter &in_first, iter in_last )
    { return range_proxy< iter >( in_first, in_last ); }

template< typename iter, typename container >
range_proxy< iter > visible_range( iter &first, container &in_container )
    { return range_proxy< iter >( first, in_container ); }

Usage:

用法:

#include <vector>
#include <iostream>
std::vector< int > values{ 1, 3, 9 };

int main() {
    // Either provide one iterator to see it through the whole container...
    std::vector< int >::iterator i;
    for ( auto &value : visible_range( i, values ) )
        std::cout << "# " << i - values.begin() << " = " << ++ value << '\n';

    // ... or two iterators to see the first incremented up to the second.
    auto j = values.begin(), end = values.end();
    for ( auto &value : visible_range( j, end ) )
        std::cout << "# " << j - values.begin() << " = " << ++ value << '\n';
}

回答by payload

I tried myself on this and found a solution.

我对此进行了尝试并找到了解决方案。

Usage:

用法:

for(auto i : ForIterator(some_list)) {
    // i is the iterator, which was returned by some_list.begin()
    // might be useful for whatever reason
}

The implementationwas not that difficult:

实现并不难:

template <typename T> struct Iterator {
    T& list;
    typedef decltype(list.begin()) I;

    struct InnerIterator {
        I i;
        InnerIterator(I i) : i(i) {}
        I operator * () { return i; }
        I operator ++ () { return ++i; }
        bool operator != (const InnerIterator& o) { return i != o.i; }
    };

    Iterator(T& list) : list(list) {}
    InnerIterator begin() { return InnerIterator(list.begin()); }
    InnerIterator end() { return InnerIterator(list.end()); }
};
template <typename T> Iterator<T> ForIterator(T& list) {
    return Iterator<T>(list);
}

回答by Ragesh Chakkadath

range basedforloop is created as the c++ counterpart for foreachin java that allows easy iteration of array elements. It is meant for removing the usage of complex structures like iterators so as to make it simple. I you want an iterator, as Nawaz said, you will have to use normal forloop.

基于范围的for循环被创建为foreachjava 中的 c++ 对应物,它允许轻松迭代数组元素。它旨在消除迭代器等复杂结构的使用,使其变得简单。我想要一个iterator,正如 Nawaz 所说,你将不得不使用普通for循环。

回答by PulseJet

There is a very simple way of doing this for std::vector, which should also work if you are resizing the vector during the process (I'm not sure whether the accepted answer considers this case)

有一种非常简单的方法可以做到这一点std::vector,如果您在此过程中调整向量的大小,它也应该有效(我不确定接受的答案是否考虑了这种情况)

If bis your vector, you can just do

如果b是你的载体,你可以做

for(auto &i:b){
    auto iter = b.begin() + (&i-&*(b.begin()));
}

where iterwill be your required iterator.

iter你需要的迭代器在哪里。

This takes advantage of the fact that C++ vectors are always contiguous.

这利用了C++ 向量始终是连续的这一事实。

回答by mbusch

Let's do it very dirty ... I know, the 0x70h is changing with stack-usage, compiler version, .... It should be exposed by the compiler, but it is not :-(

让我们做得很脏......我知道,0x70h 正在随着堆栈使用、编译器版本等而变化......它应该由编译器公开,但它不是:-(

char* uRBP = 0; __asm { mov uRBP, rbp }
Iterator** __pBegin = (Iterator**)(uRBP+0x70);
for (auto& oEntry : *this) {
    if (oEntry == *pVal) return (*__pBegin)->iPos;
}