Python 如何对一个数字进行立方
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How to cube a number
提问by user3795416
I just started using Python today for my class and one of my problems is cubing a number in Python. I know the way to do it is x^3, but that doesn't work in Python. I was just wondering how I would be able to do that.
我今天刚开始在课堂上使用 Python，我的问题之一是在 Python 中对数字求立方。我知道这样做的方法是x^3，但这在 Python 中不起作用。我只是想知道我怎么能做到这一点。
This is what I tried so far, but as you can see, I keep getting syntax errors:
这是我到目前为止所尝试的，但正如您所看到的，我不断收到语法错误：
>>> def volume (v) :
return v^3
volume(4)
SyntaxError: invalid syntax
回答by kojiro
Actually different symbols mean different things in different programming languages. In some languages, ^means exponent, but in Python, the exponent operator symbol is **:
实际上，不同的符号在不同的编程语言中意味着不同的东西。在某些语言中，^表示指数，但在 Python 中，指数运算符符号是**：
>>> 3**3
27
The ^symbol is for the bitwise 'xor' operation:
该^符号用于按位“异或”运算：
>>> 1^1
0
>>> 1^0
1
Read the documentation on the operator moduleto see how Python really treats these symbols.
阅读有关operator 模块的文档以了解 Python 如何真正处理这些符号。
回答by Rafael Barros
You can use the **operator to do exponential calculations.
您可以使用**运算符进行指数计算。
def volume(v)
return v**3
回答by Rafael Barros
Python uses the **operatorfor exponentiation, not the ^operator(which is a bitwise XOR):
Python 使用**运算符来求幂，而不是^运算符（它是按位异或）：
>>> 3*3*3
27
>>>
>>> 3**3 # This is the same as the above
27
>>>
Note however that the syntax error is being raised because there is no newline before volume(4):
但是请注意，由于之前没有换行符，因此会引发语法错误volume(4)：
>>> def volume(v):
... return v**3
... volume(4)
File "<stdin>", line 3
volume(4)
^
SyntaxError: invalid syntax
>>>
>>> def volume(v):
... return v**3
... # Newline
>>> volume(4)
64
>>>
When you are in the interactive interpreter, the newline lets Python know that the definition of function volumeis finished.
当您在交互式解释器中时，换行符让 Python 知道函数定义volume已完成。
回答by Nobi
Use the *key twice
使用*钥匙两次
def volume (v) :
return v**3
volume(4)
回答by Nobi
Use two asteric's between the number and the power. Ex 2^5in math is 2**5in python. You can also do something along the lines of math.pow(100, 2) = 10000.0.
在数字和幂之间使用两个星号。2^5数学2**5中的Ex在 python 中。你也可以做一些类似的事情math.pow(100, 2) = 10000.0。
回答by yogesh
The Best way to do this is
最好的方法是
cube = lambda x: x**3
cube(3)
but one another solution be like which result in the same
但另一种解决方案就像结果一样
cube = lambda x: x*x**2
cube(3)
one another alter solution be like
另一个改变解决方案就像
math.pow(3,3)
all will return the cube of number 3.
all 将返回数字 3 的立方体。
回答by Shavaiz Shams
I have tried this with using a simple printfunction, you can calculate the cube by using **operators
我已经用一个简单的print函数试过了，你可以使用**运算符来计算立方体
a = int(input())
b = int(input())
print(a**3)
print(b**3)
回答by hanumanDev
def volume(v):
result = v * v * v
return result
print("enter a number to be cubed: ")
print(volume(int(input())))
or
或者
def volume(v):
result = v ** 3
return result
print("enter a number to be cubed: ")
print(volume(int(input())))
回答by user212514
Your syntax is attempting to use ^as the exponentiation operator, but you should be using the **operator. For example:
您的语法试图^用作求幂运算符，但您应该使用该**运算符。例如：
>>> def volume (v) :
... return v ** 3
...
>>> volume(4)
64
