错误代码:mysql 中的 1064

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时间:2020-08-31 21:28:01  来源:igfitidea点击:

Error Code: 1064 in mysql

mysqlmysql-error-1064

提问by Rehme

I created a procedure that is supposed to do some operation but every time I call it, mysql comes out with an error, which I have not clue what it means. I have tried to understand it in vain, here 's the table structure which the stored procedure where made to do an operation on it:

我创建了一个应该执行某些操作的过程,但是每次调用它时,mysql 都会出现错误,我不知道它的含义。我试图理解它是徒劳的,这是存储过程对其进行操作的表结构:

CREATE  TABLE `recruitment`.`job_seeker` (
    `user_id` INT Null ,
    `fname` VARCHAR(45) Null ,
    `lname` VARCHAR(45) Null ,
    `mname` VARCHAR(45) Null ,
    `gender` VARCHAR(10) Null ,
    `dob` DATE Null ,
    `marital_status` VARCHAR(45) Null ,
    `address` VARCHAR(45) Null ,
    `city` VARCHAR(45) Null ,
    `nationality` VARCHAR(45) Null ,
    `phone` VARCHAR(45) Null ,
    `mobile` VARCHAR(45) Null ,
    `degree_id` INT Null ,
    `education` VARCHAR(100) Null ,
    `experience` VARCHAR(250) Null ,
    `other` VARCHAR(250) Null ,
    `job_target` VARCHAR(250) Null ,
    PRIMARY KEY (`user_id`) ,
    INDEX `user_id` (`user_id` ASC) ,
    INDEX `degree_id` (`degree_id` ASC) ,
    CONSTRAINT `user_id`
    FOREIGN KEY (`user_id` )
    REFERENCES `recruitment`.`user_authentication` (`user_id` )
    ON DELETE NO ACTION
    ON UPDATE NO ACTION,
    CONSTRAINT `degree_id`
    FOREIGN KEY (`degree_id` )
    REFERENCES `recruitment`.`degree` (`degree_id` )
    ON DELETE NO ACTION
    ON UPDATE NO ACTION
);

Here's the stored procedure:

这是存储过程:

DELIMITER $$

CREATE DEFINER=`root`@`localhost` PROCEDURE `createSeekerProfile`(in userName varchar(45),
    in fn varchar(45),in mn varchar(45), in ln varchar(45),
    in gender varchar(6),in nationality varchar(45),
    in ad varchar(45),in city varchar(45),in phone varchar(15),in mob varchar(15),

    in   maritalStatus varchar(45), in degId int, in educ varchar(100),
    in exper varchar(250), in other   varchar(250),
    in dob date,in jtarg varchar(250))
    begin
    declare returned_ID int;
    set @dyn_que = CONCAT('select user_id into @returned_ID
    from user_authentication where user_name =  ? ');
    prepare s1 from @dyn_que ;
set @usn = userName;
execute s1 using @usn ;

set @dyn_update =CONCAT('update job_seeker set fname =',fn,', lname = ',ln,' ,mname = ',mn,' ,
nationality =',nationality,',address =',ad,',city =',city,',phone=',phone,',
mobile =',mob,', gender = ',gender,',other =',other,',
degree_id =',degId,', job_target=',jtarg,', dob =',dob,', education =',educ,',
experience=',exper,', marital_status=',maritalStatus,' where user_id =@returned_ID');
prepare s2 from @dyn_update;
execute s2;
end

Whenever I call the procedure through:

每当我通过以下方式调用程序时:

call createSeekerProfile('realsilhouette','robert','marie','david','male'
,'earthal','an address here','capital of earth','012178152',
'1111111111','single',2,'engineering','looking forward','determined',
'2008-7-04','Oracle CEO')

I get an awful error which is:

我得到一个可怕的错误是:

Error Code: 1064
You have an error in your SQL syntax; check the manual that corresponds
to your MySQL server version for the right syntax to use near 'address here,
city =capital of earth,phone=012178152,
mobile =1111111111, gender' at line 2

However when I try execute the update statement manually which is inside stored procedure, it works out so well.

但是,当我尝试手动执行存储过程中的更新语句时,效果很好。

new Post : thanks god,finally I fixed the problem up, The problem came down to the order, all I did was just make the parameters in order, though update statement does not care about the order, as far as I know, I'm not sure, But what i am sure of is the stored procedure got created beautifully, here's the new code :

new Post : 感谢上帝,终于把问题解决了,问题归结为顺序,我所做的只是将参数按顺序排列,虽然更新语句不关心顺序,据我所知,我'我不确定,但我确信存储过程创建得很漂亮,这是新代码:

DELIMITER $$

CREATE DEFINER=`root`@`localhost` PROCEDURE `createSeekerProfile`(
in un varchar(45),
in fn varchar(45),
in ln varchar(45), 
in mn varchar(45),
in g varchar(10),
in dateOfBirth date,
in ms varchar(45),
in ad varchar(45),
in city varchar(45),
in nat varchar(45),
in ph varchar(45),
in mob varchar(45),
in degid int,
in educ varchar(100),
in exp varchar(250),
in other varchar(250),
in jtarg varchar(250))
begin

declare returned_ID int(11);

 set @dyn_que = CONCAT('select user_id into @returned_ID from user_authentication
 where user_name =  ? ');
 prepare s1 from @dyn_que ;
 set @usn = un;
 execute s1 using @usn ;


 set @dyn_update =CONCAT('update job_seeker set fname  
 ="',fn,'",lname="',ln,'",mname="',mn,'",lname ="',ln,'",
 gender ="',g,'",dob="',dateOfBirth,'",marital_status="',ms,'",
 address="',ad,'",city="',city,'",
 nationality="',nat,'",phone="',ph,'",mobile="',mob,'",degree_id="',
 degid,'",education="',educ,'",
 experience="',exp,'",other="',other,'",job_target="',jtarg,'" 
 where user_id = @returned_ID');
 prepare stm from @dyn_update;
 execute stm;
 end $$

many thanks

非常感谢

采纳答案by ravnur

Your forgot about quoting string values.

您忘记了引用字符串值。

for example:

例如:

concat('update yourTable
set address ="',  @address, '" 
where id = 1');

or use function quote

或使用函数引用

回答by shreyas

For me adding character ` (GRAVE ACCENT) helped. It is not a single quote (')

对我来说,添加字符`(重音符号)有帮助。它不是单引号 (')

回答by Muhammad Siddique Awan

CREATE TABLE Order
( 
    Order_Id             integer  NOT NULL ,
    Order_Time           datetime  NULL ,
    Order_Status         char(50)  NULL ,
    Customer_Id          integer  NOT NULL 
)