java 合并两个正则表达式
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merge two regular expressions
提问by KristianMedK
I have two regular expressions, one pulling out usernames from a csv string, and the other pulling out emails.
我有两个正则表达式，一个从 csv 字符串中提取用户名，另一个提取电子邮件。
the string format is like this:
字符串格式是这样的：
String s = "name lastname (username) <[email protected]>; name lastname (username) <[email protected]>; name lastname (username) <[email protected]>";
the code for my regular expressions are like this.
我的正则表达式的代码是这样的。
Pattern pattern = Pattern.compile("(?<=\()[^\)]+");
Matcher matcher = pattern.matcher(s);
Pattern pattern2 = Pattern.compile("((?<=<)[^>]+)");
Matcher matcher2 = pattern2.matcher(s);
while (matcher.find() && matcher2.find()) {
System.out.println(matcher.group() + " " + matcher2.group());
}
I've found several qeustions about merging regexes, but from the answers i haven't been able to figure out how to merge mine.
我发现了几个关于合并正则表达式的问题，但从答案中我无法弄清楚如何合并我的。
my printouts show:
我的打印输出显示：
"username [email protected]"
would I be able to print out the samefrom a single matcher, using one regex?
我可以使用一个正则表达式从单个匹配器中打印出相同的内容吗？
obs: this is a school assignment, which means i do not "need" to merge them or do any more, but i'd like to know if it is possible, and how difficult it would be.
obs：这是一项学校作业，这意味着我不需要“合并”它们或做更多事情，但我想知道是否有可能，以及这会有多困难。
回答by Rohit Jain
You can just use an Pipe (|)in between your multiple Regex, to match all of them : -
您可以Pipe (|)在 , 之间使用一个inmultiple Regex来匹配所有这些：-
String s = "name lastname (username) <[email protected]>; name lastname
(username) <[email protected]>; name lastname
(username) <[email protected]>;";
// Matches (?<=\()[^\)]+ or ((?<=<)[^>]+)
Pattern pattern = Pattern.compile("(?<=\()[^\)]+|((?<=<)[^>]+)");
Matcher matcher = pattern.matcher(s);
while (matcher.find()) {
System.out.println(matcher.group());
}
OUTPUT: -
输出：-
username
[email protected]
username
[email protected]
username
[email protected]
UPDATE: -
更新：-
If you want to print usernameand emailonly when they both exists, then you need to split your string on ;and then apply the below Regex on each of them.
如果您想打印username并且email仅当它们都存在时，那么您需要拆分您的字符串;，然后在每个字符串上应用以下正则表达式。
Here's the code: -
这是代码： -
String s = "name lastname (username) ;
name lastname (username) <[email protected]>;
name lastname (username) <[email protected]>;";
String [] strArr = s.split(";");
for (String str: strArr) {
Pattern pattern = Pattern.compile("\(([^\)]+)(?:\))\s(?:\<)((?<=<)[^>]+)");
Matcher matcher = pattern.matcher(str);
while (matcher.find()) {
System.out.print(matcher.group(1) + " " + matcher.group(2));
}
System.out.println();
}
OUTPUT: -
输出：-
username [email protected]
username [email protected] // Only the last two have both username and email
回答by brimborium
The following code will extract your pairs. The regex is quite short, but I am almost sure, there is a more elegant way (there always is with regex!). ;)
以下代码将提取您的配对。正则表达式很短，但我几乎可以肯定，有一种更优雅的方式（正则表达式总是存在的！）。;)
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Main {
public static void main(String[] args) {
String s = "name1 lastname1 (user1); name2 lastname2 (username2) <[email protected]>; name3 lastname3 (username3) <[email protected]>;";
Pattern pattern = Pattern.compile("\(([^\)]+)\)\s<([^>]+)>");
Matcher matcher = pattern.matcher(s);
while (matcher.find()) {
System.out.println(matcher.group(1) + " " + matcher.group(2));
}
}
}
Output:
输出：
username2 [email protected]
username3 [email protected]
用户名2 [email protected]
用户名3 [email protected]
Explanation for the regex "\\(([^\\)]+)\\)\\s<([^>]+)>":
正则表达式的解释"\\(([^\\)]+)\\)\\s<([^>]+)>"：
\\(([^\\)]+)\\): A group of non-)characters enclosed by(and)\\s: A space in between<([^>]+)>: A group of non->characters enclosed by<and>
\\(([^\\)]+)\\):)由(和包围的一组非字符)\\s: 中间有空格<([^>]+)>:>由<和包围的一组非字符>
