如何为 C# XML 序列化添加属性
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How to add attributes for C# XML Serialization
提问by user107779
I am having an issue with serializing and object, I can get it to create all the correct outputs except for where i have an Element that needs a value and an attribute. Here is the required output:
我在序列化和对象方面遇到问题，我可以让它创建所有正确的输出，除了我有一个需要值和属性的元素。这是所需的输出：
<Root>
<Method>Retrieve</Method>
<Options>
<Filter>
<Times>
<TimeFrom>2009-06-17</TimeFrom>
</Times>
<Document type="word">document name</Document>
</Filter>
</Options>
</AdCourierAPI>
I can build all of it but can not find a way to set the Document type attribute, here is a segment of the object class
我可以构建所有这些但找不到设置文档类型属性的方法，这是对象类的一部分
[XmlRoot("Root"), Serializable]
public class Root
{
[XmlElement("Method")]
public string method="RetrieveApplications";
[XmlElement("Options")]
public _Options Options;
}
public class _Options
{
[XmlElement("Filter")]
public _Filter Filter;
}
public class _Filter
{
[XmlElement("Times")]
public _Times Times;
[XmlElement("Documents")]
public string Documents;
}
which gives me:
这给了我：
<Document>document name</Document>
rather than:
而不是：
<Document type="word">document name</Document>
but I can not find a way to correct this, please advise.
但我找不到纠正这个问题的方法，请指教。
Thanks
谢谢
采纳答案by bruno conde
Where do you have the typestored?
你type储存在哪里？
Normally you could have something like:
通常你可以有这样的东西：
class Document {
[XmlAttribute("type")]
public string Type { get; set; }
[XmlText]
public string Name { get; set; }
}
public class _Filter
{
[XmlElement("Times")]
public _Times Times;
[XmlElement("Document")]
public Document Document;
}
回答by Thomas Levesque
The stringclass doesn't have a typeproperty, so you can't use it to create the desired output. You should create a Documentclass instead :
该string班没有一个type属性，所以你不能用它来创建所需的输出。您应该创建一个Document类：
public class Document
{
[XmlText]
public string Name;
[XmlAttribute("type")]
public string Type;
}
And you should change the Documentproperty to type Document
您应该将Document属性更改为类型Document
回答by Marc Gravell
It sounds like you need an extra class:
听起来您需要额外的课程：
public class Document
{
[XmlAttribute("type")]
public string Type { get; set; }
[XmlText]
public string Name { get; set; }
}
Where an instance (in the example) would have Type = "word"and Name = "document name"; documentswould be a List<Document>.
实例（在示例中）将具有Type = "word"和的位置Name = "document name"；documents将是一个List<Document>.
By the way - public fields are rarely a good idea...
顺便说一句 - 公共领域很少是一个好主意......
回答by Krzysztof Juszcze
You can use XmlWriter instead XmlSerialization to get this effect. It is more complex but if you have a lot of strings in model it will be cleaner solution.
您可以使用 XmlWriter 代替 XmlSerialization 来获得此效果。它更复杂，但如果模型中有很多字符串，它将是更清晰的解决方案。
Create your own CustomeAttribute, for example:
创建您自己的 CustomeAttribute，例如：
[System.AttributeUsage(AttributeTargets.Property, AllowMultiple = false)]
public class MyCustomAttribute : System.Attribute
{
public MyCustomAttribute (string type)
{
MyType = type;
}
public string MyType { get; set; }
}
Then in model add it, like that:
然后在模型中添加它，就像这样：
public class MyModel
{
[MyCustom("word")]
public string Document { get; set; }
[MyCustom("time")]
public string Time { get; set; }
}
The last part is to create xml with this arguments. You can do it likes that:
最后一部分是使用此参数创建 xml。你可以这样做：
var doc = new XmlDocument();
MyModel myModel = new MyModel();//or get it from somewhere else
using (Stream s = new MemoryStream())
{
var settings = new XmlWriterSettings();
settings.Async = true;
settings.Indent = true;
var writer = XmlTextWriter.Create(s, settings);
await writer.WriteStartDocumentAsync();
await writer.WriteStartElementAsync(null,"Root", null);
myModel.GetType().GetProperties().ToList().ForEach(async p =>
{
dynamic value = p.GetValue(myModel);
writer.WriteStartElement(p.Name);
var myCustomAttribute = p.GetCustomAttributes(typeof(MyCustomAttribute), false).FirstOrDefault() as MyCustomAttribute;
if(myCustomAttribute != null)
{
await writer.WriteAttributeStringAsync(null, "MyType", null, myCustomAttribute.MyType );
}
writer.WriteValue(value);
await writer.WriteEndElementAsync();
});
await writer.WriteEndElementAsync();
await writer.FlushAsync();
s.Position = 0;
doc.Load(s);
writer.Close();
}
string myXml = doc.OuterXml
In myXml should be something like that: (values are examples)
在 myXml 中应该是这样的：（值是示例）
<?xml version="1.0" encoding="utf-8"?>
<Root>
<Document MyType="word">something</Document>
<Time MyType="time">11:31:29</Time>
</Root>
You can do it in other way, of course. Here you have some docs which helped me: https://docs.microsoft.com/en-us/dotnet/api/system.xml.xmlwriter?view=netframework-4.8#writing_elements
当然，您可以通过其他方式来实现。这里有一些对我有帮助的文档：https: //docs.microsoft.com/en-us/dotnet/api/system.xml.xmlwriter?view=netframework-4.8# writing_elements
