ios 在初始化时将参数传递给自定义类
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Passing parameters to a custom class on initialization
提问by user567
I have a class Messagewith two attributes, nameand message, and another class MessageControllerwith two text fields, nameFieldand messageField.
I want to make an instance of Messagein MessageController, passing these two attributes as arguments.
我有一个Message有两个属性的类，name和message，另一个MessageController有两个文本字段的类，nameField和messageField。我想创建一个Messagein实例MessageController，将这两个属性作为参数传递。
Right now, I am doing this:
现在，我正在这样做：
Message *messageIns = [[Message alloc] init];
messageIns.name = nameField;
messageIns.message = MessageField;
How can I pass the values at the creation of an instance?
I tried to redefine initin Message.m, but I don't know how do that.
如何在创建实例时传递值？我试图init在 Message.m 中重新定义，但我不知道该怎么做。
-(id)init{
if((self=[super init])){
}
return self;
}
Please help.
请帮忙。
回答by Giuliano Galea
You have to create a custom initializer.
您必须创建一个自定义初始化程序。
-(id)initWithName:(NSString *)name_ message:(NSString *)message_
{
self = [super init];
if (self) {
self.name = name_;
self.message = message_;
}
return self;
}
of course this assumes your parameters are of NSString type and that you have your properties set correctly ;)
当然，这假设您的参数是 NSString 类型，并且您的属性设置正确；)
