ios UITapGestureRecognizer 选择器，sender 是手势，不是 ui 对象
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UITapGestureRecognizer selector, sender is the gesture, not the ui object
提问by dysan819
I have a series of imageviews that I identify using their tag. I have added a single tap gesture to the images.
我有一系列使用它们的标签识别的图像视图。我在图像中添加了一个单击手势。
UITapGestureRecognizer *singleTap = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(selectImage:)];
[tableGridImage addGestureRecognizer:singleTap];
tableGridImage.userInteractionEnabled = YES;
[singleTap release];
This manages to call the selectImage selector ok, but passes the gesture as the sender. I need the imageview as the sender so I can get the tag.
这设法调用 selectImage 选择器，但将手势作为发送者传递。我需要 imageview 作为发件人，以便我可以获得标签。
Any ideas on how I can get the imageview and it's tag?
关于如何获取图像视图及其标签的任何想法？
回答by dysan819
I figured out how to get the tag, which was the most important part of the question for me. Since the gesture is the sender, I figured out the the view it is attached to is sent along with it:
我想出了如何获取标签，这对我来说是问题中最重要的部分。由于手势是发送者，我发现它所附加的视图是随它一起发送的：
[(UIGestureRecognizer *)sender view].tag
I am still curious if anyone can tell me how to send an argument through a UITapGestureRecognizer selector.
我仍然很好奇是否有人能告诉我如何通过 UITapGestureRecognizer 选择器发送参数。
回答by Samidjo
The only argument you can send through UITapGestureRecognizer selector is the UITapGestureRecognizer itself as following:
您可以通过 UITapGestureRecognizer 选择器发送的唯一参数是 UITapGestureRecognizer 本身，如下所示：
Make sure to put ":" after the selector name like you previously did :
确保像以前一样在选择器名称之后放置“ ：”：
UITapGestureRecognizer *singleTap =
[[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(selectImage:)];
Then add a parameter to selectImage so you can retrieve the View as following:
然后向 selectImage 添加一个参数，以便您可以按如下方式检索视图：
-(void) selectImage:(UITapGestureRecognizer *)gestureRecognizer{
//Get the View
UIImageView *tableGridImage = (UIImageView*)gestureRecognizer.view;
}
回答by Dody Rachmat Wicaksono
From @dysan819 answer, I manage to get object without tag. In my case is UILabel.
从@dysan819 的答案中，我设法获得了没有标签的对象。在我的情况下是UILabel.
- (void)labelTap:(id)sender {
NSLog(@"tap class: %@", [[(UIGestureRecognizer *)sender view] class]);
if ([[(UIGestureRecognizer *)sender view] isKindOfClass:[UILabel class]]) {
UILabel *lb = (UILabel*)[(UIGestureRecognizer *)sender view];
NSLog(@"tap: %@", lb.text);
}
}
回答by Norman H
If you need distinct functionality for the handler you might check out the BlocksKit project and thisfile in particular. The project is a CocoaPodsproject so you can install it easily into your toolchain.
如果您需要处理程序的独特功能，您可以查看 BlocksKit 项目，特别是这个文件。该项目是一个CocoaPods项目，因此您可以轻松地将其安装到您的工具链中。
An example from the first referenced code file:
第一个引用的代码文件中的示例：
UITapGestureRecognizer *singleTap = [UITapGestureRecognizer recognizerWithHandler:^(id sender) {
NSLog(@"Single tap.");
} delay:0.18];
[self addGestureRecognizer:singleTap];
This could effectively allow you to setup a gesture recognizer easily for each image.
这可以有效地让您轻松地为每个图像设置手势识别器。
