JavaScript - 创建对象并使用变量作为属性名称？
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JavaScript - creating object and using variable for property name?
提问by PruitIgoe
I am creating my own object:
我正在创建自己的对象：
gridObject = new Object();
I'm then using jquery to pull the contents of list item tags, which themselves are filled with
然后我使用 jquery 来提取列表项标签的内容，这些标签本身就充满了
tags that have specific class names:
具有特定类名的标签：
<li row="1"><p class="department" rowitem="department">Photography</p>...</li>
I'm pulling them using this code:
我正在使用此代码拉它们：
//make object from results
gridObject = new Object();
//get all the rows
var rowlist = $('li[row]');
for(var r=0; r<rowlist.length; r++) {
//make gridObject row element here
//get the row content
var thisrow = $(rowlist[r]).html();
//get all the p tags
var rowitems = $(thisrow + 'p.[rowitem]');
//get field name
for(var ri=0; ri<rowitems.length; ri++) {
if (r < 2) { //this is temporary just for testing
var fieldname = $(rowitems[ri]).attr('rowitem');
var fieldvalue = $(rowitems[ri]).html();
}
}
I'm getting hung up passing this into my object. Two questions. Can an object property be made with a variable name, like so
我在将它传递给我的对象时被挂断了。两个问题。可以使用变量名称创建对象属性吗，像这样
griObject.fieldname = fieldvalue;
and can the objects have parent/child relationships such as:
对象是否可以具有父/子关系，例如：
gridObject.r.fieldname = fieldvalue;
in this case both r and fieldname would be variables. Or should I just be working associative arrays to achieve something similar?
在这种情况下， r 和 fieldname 都是变量。或者我应该只是使用关联数组来实现类似的功能？
This is in answer to a follow up question I posted below, "is there a print_r equivalent in javascript" - you can use iterator, a bit more typing but does the trick:
这是对我在下面发布的后续问题的回答，“javascript 中是否有 print_r 等效项”-您可以使用迭代器，输入更多内容，但可以解决问题：
//loop through search data
var it = Iterator(filteritems);
for(var pair in it) {
console.log("key:" + pair[0] + ", value:" + pair[1] + "\n");
}
回答by Skilldrick
If you want to use a variable property name, use subscript syntax:
如果要使用变量属性名称，请使用下标语法：
var fieldname = 'test';
//These two lines are equivalent as long as fieldname is 'test':
gridObject[fieldname] = fieldvalue;
gridObject.test = fieldvalue
