Java 使用或覆盖已弃用的 API
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时间：2020-08-13 13:41:27 来源:igfitidea点击:
Java uses or overrides a deprecated API
提问by user3368306
I have written a code for my project and I am getting a warning message when I compile. I could not run it. Having tried many possible ways like ignoring warning and etc, I am still unable to run it. Below you will find the code.
我已经为我的项目编写了代码，并且在编译时收到一条警告消息。我无法运行它。尝试了许多可能的方法，例如忽略警告等，我仍然无法运行它。您将在下面找到代码。
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
import java.io.*;
import java.net.*;
import java.util.*;
import javax.swing.event.*;
import java.sql.*;
class NymbleServer extends JFrame
{
JLabel jl1;
JLabel jl2;
JButton jb1;
JButton jb2;
JTextField jt1;
JPasswordField jt2;
String msg="";
Container c;
ImageIcon ii;
ImageIcon i2;
JLabel jl4;
JLabel jl6;
String str="";
String pass="";
String path="";
String coreaddr="";
String core="";
String nextcore="";
String dest="";
String dest1="";
File f;
File fgs;
Vector v = new Vector();
NymbleServer()
{
jl1=new JLabel("Nymble Server Name ");
jl2=new JLabel("Server Key ");
jb1=new JButton("Send");
jb2=new JButton("Reset");
jt1=new JTextField(10);
jt2=new JPasswordField(10);
ii=new ImageIcon("nymbleserver.png");
i2=new ImageIcon("nymbleserver1.PNG");
jl4=new JLabel(ii);
jl6=new JLabel(i2);
c = getContentPane();
c.setLayout(null);
c.setBackground(new Color(0,0,120));
c.show();
c.add(jl1);
c.add(jt1);
c.add(jl2);
c.add(jb1);
c.add(jb2);
c.add(jl4);
c.add(jl6);
c.add(jt2);
addWindowListener(new java.awt.event.WindowAdapter() {
public void windowClosing(java.awt.event.WindowEvent evt) {
exitForm(evt);
}
});
jl4.setBounds(30,20,728,68);
jl1.setBounds(20,110,200,25);
jt1.setBounds(150,110,100,25);
jl2.setBounds(50,145,200,25);
jt2.setBounds(150,145,100,25);
jb1.setBounds(70,235,100,25);
jb2.setBounds(180,235,100,25);
jl6.setBounds(300,105,485,309);
setSize(800,500);
setVisible(true);
setTitle("Server");
jb1.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent ae)
{
try {
if(!jt1.getText().equals("") && !jt2.getText().equals("")){
JOptionPane.showMessageDialog (null, "Authorised User", "Login
Seccess", JOptionPane.INFORMATION_MESSAGE);
VerifAdminLogin();
}
else
JOptionPane.showMessageDialog((Component) null,
"Invalid password. Please try again. ", "Login Error",
JOptionPane.INFORMATION_MESSAGE);
}
catch(Exception e) { System.out.println(e);
}
}
});
jb2.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent ae)
{
jt1.setText("");
jt2.setText("");
}
});
}
private void exitForm(java.awt.event.WindowEvent evt)
{
dispose();
}
public static void main(String a[])
{
new FileOpen();
}
void VerifAdminLogin()
{
Connection con=null;
String url="jdbc:odbc:nymble";
Statement st=null;
try
{
String val1=jt1.getText();
val1 = val1.trim();
String val2 =
(String)jt2.getText();
val2 = val2.trim();
Class.forName
("sun.jdbc.odbc.JdbcOdbcDriver");
con=DriverManager.getConnection(url);
st = con.createStatement();
ResultSet rs=st.executeQuery("Select Key from
Server where SerName='"+val1+"'");
while(rs.next()){
String user = rs.getString(1);
boolean b=user.equals(val2);
if(b)
{
new Server().setVisible(true);
}
else
{
JOptionPane.showMessageDialog
((Component) null, "Invalid password. Please try again. ", "Login Error",
JOptionPane.INFORMATION_MESSAGE);
jt1.setText("");
jt2.requestFocus();
}
}
}
catch(SQLException ex)
{
System.out.println("Unable to access the database");
}
catch(ClassNotFoundException ex)
{
System.out.println("Class not found");
}
catch(Exception ex)
{
System.out.println("Exception raised is:"+ex);
}
finally {
con=null;
}
}
}
回答by Bitman
Just replace
只需更换
new PseudonymManager().show();
with
和
new PseudonymManager().setVisible(true);
Method show() was deprecated since java 1.5 so just read java docs next time;)
方法 show() 从 java 1.5 开始被弃用，所以下次只需阅读 java 文档；)
