在同一行 Bash 上排序
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Sorting on Same Line Bash
提问by Tom Gorski
Hello I am trying to sort a set of numeric command line arguments and then echo them back out in reverse numeric order on the same line with a space between each. I have this loop:
您好，我正在尝试对一组数字命令行参数进行排序，然后在同一行中以相反的数字顺序将它们回显出来，每个参数之间有一个空格。我有这个循环：
for var in "$@"
do
echo -n "$var "
done | sort -rn
However when I added the -nto the echo the sortcommand stops working. I am trying to do this without using printf. Using the echo -nthey do not sort and simply print in the order they were entered.
但是，当我将 the 添加-n到 echo 时，sort命令停止工作。我正在尝试不使用printf. 使用echo -n它们不排序，只是按照输入的顺序打印。
回答by anubhava
You can do it like this:
你可以这样做：
a=( $@ )
b=( $(printf "%s\n" ${a[@]} | sort -rn) )
printf "%s\n" ${b[@]}
# b is reverse sorted nuemrically now
回答by devnull
man sortwould tell you:
man sort会告诉你：
sort - sort lines of text files
So you can transform the result into the desired format aftersorting.
所以你可以在排序后将结果转换为所需的格式。
In order to achieve the desired result, you can say:
为了达到预期的结果，您可以说：
for var in "$@"
do
echo "$var"
done | sort -rn | paste -sd' '
回答by Cole Tierney
One trick is to play with the IFS:
一个技巧是玩 IFS：
IFS=$'\n'
set "$*"
IFS=$' \n'
set $(sort -rn <<< "$*")
echo $*
This is the same idea but easier to read with the join() function:
这是相同的想法，但使用 join() 函数更容易阅读：
join() {
IFS=
shift
echo "$*"
}
join ' ' $(join $'\n' $* | sort -nr)
回答by matteoeghirotta
Maybe that's because sort is "line-oriented", so you need every number on a separate line, which is not the case using -n with echo. You could simply put the sorted numbers back in one line using sed, like that:
也许这是因为 sort 是“面向行的”，因此您需要将每个数字都放在单独的行上，而将 -n 与 echo 结合使用则不是这种情况。您可以简单地使用 sed 将排序后的数字放回一行，如下所示：
for var in "$@";
do
echo "$var ";
done | sort -rn | sed -e ':a;N;s/\n/ /;ba'
回答by zakinster
sortis used to sort multiple lines of text. Using the option -nof echo, you are printing everything in one line.
If you want the output to be sorted, you have to print it in multiple lines :
sort用于对多行文本进行排序。使用选项-n中echo，你是在一行中打印的一切。如果要对输出进行排序，则必须将其打印成多行：
for var in "$@"
do
echo $var
done | sort -rn
If you want the result on only one line you could do :
如果你只想要一行的结果，你可以这样做：
echo $(for var in "$@"; do echo $var; done | sort -rn)
