C语言 如何#define unsigned char* 字符串？
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How do I #define an unsigned char* string?
提问by Dehalion
I have following define in my code
我在我的代码中有以下定义
#define PRODUCTNAME "SomeName"
and I want to send it with a function com_reply(unsigned char* msg, uint16_t lenght).
我想用一个函数发送它com_reply(unsigned char* msg, uint16_t lenght)。
Now I get a warning that my argument differs in signedness. I know what the problem is and also why com_replyuses unsigned char*instead of char*, I just want to know:
现在我收到一个警告，说我的论点在符号上有所不同。我知道问题是什么以及为什么com_reply使用unsigned char*而不是char*，我只想知道：
How can I define my string as an unsigned char*so I can use it throughout my program without getting warnings all over the place.
如何将我的字符串定义为 anunsigned char*以便我可以在整个程序中使用它而不会到处都收到警告。
EDIT:
编辑：
Strictly speaking I have more than one defines here and the main reason is that there is a BANNERdefine which consists of several other defines, like this:
严格来说，我在这里有多个定义，主要原因是有一个BANNER定义包含其他几个定义，如下所示：
#define PRODUCTNAME "SomeName"
#define PRODUCTDATE "2013-03-30"
#define BANNER PRODUCTNAME " (" PRODUCTDATE ")"
Should I create const variables and concatenate them at program start instead of using defines here?
我应该创建 const 变量并在程序开始时连接它们而不是在此处使用定义吗？
回答by thumbmunkeys
This should work:
这应该有效：
#define PRODUCTNAME ((const unsigned char *)"SomeName")
