ios Swift：将参数传递给选择器
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Swift: Passing a parameter to selector
提问by user1107173
Using Swift 3, Xcode 8.2.1
使用 Swift 3，Xcode 8.2.1
Method:
方法：
func moveToNextTextField(tag: Int) {
print(tag)
}
The lines below compile fine, but taghas an uninitialized value:
下面的行编译正常，但tag有一个未初始化的值：
let selector = #selector(moveToNextTextField)
Timer.scheduledTimer(timeInterval: 0.2, target: self, selector: selector, userInfo: nil, repeats: false)
However, I need to pass a parameter. Below fails to compile:
但是，我需要传递一个参数。下面编译失败：
let selector = #selector(moveToNextTextField(tag: 2))
Swift Compile Error:
Argument of #selector does not refer to an @objc method, property, or initializer.
How can I pass an argument to a selector?
如何将参数传递给选择器？
回答by hybridcattt
#selectordescribes method signature only. In your case the correct way to initialize the selector is
#selector仅描述方法签名。在您的情况下，初始化选择器的正确方法是
let selector = #selector(moveToNextTextField(tag:))
Timer has the common target-action mechanism. Target is usually self and action is a method that takes one parameter sender: Timer. You should save additional data to userInfodictionary, and extract it from senderparameter in the method:
定时器具有通用的目标-动作机制。目标通常是 self ，而 action 是一种接受一个参数的方法sender: Timer。您应该将其他数据保存到userInfo字典中，并从sender方法中的参数中提取它：
func moveToNextTextField(sender: Timer) {
print(sender.userInfo?["tag"])
}
...
let selector = #selector(moveToNextTextField(sender:))
Timer.scheduledTimer(timeInterval: 0.2, target: self, selector: selector, userInfo: ["tag": 2], repeats: false)
回答by vadian
You cannot pass a custom parameter through a Timeraction.
您不能通过操作传递自定义参数Timer。
Either
任何一个
#selector(moveToNextTextField)
...
func moveToNextTextField()
or
或者
#selector(moveToNextTextField(_:))
...
func moveToNextTextField(_ timer : Timer)
is supported, nothing else.
支持，没有别的。
To pass custom parameters use the userInfodictionary.
要传递自定义参数，请使用userInfo字典。
