在 C# 中，如何将 DWORD 声明为 uint32？
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In C#, How to declare DWORD as an uint32?
提问by CrashCodes
I guess the question is really about how to define a type as an existing primitive data type. Below clearly doesn't work, but I think you'll get the idea.
我想问题实际上是关于如何将类型定义为现有的原始数据类型。下面显然行不通，但我想你会明白的。
Type DWORD = typeof(UInt32);
private DWORD func1(int x)
{
return 123;
}
采纳答案by Mehrdad Afshari
There is no typedefin C#. You can't use #definemacros to replace strings either (they are just conditional). The only rough equivalent is using DWORD = System.UInt32;on top of your source file.
typedefC# 中没有。您也不能使用#define宏来替换字符串（它们只是有条件的）。唯一粗略的等效项位于using DWORD = System.UInt32;源文件的顶部。
回答by dommer
What about
关于什么
using DWORD = System.UInt32;
Downside to this is that you'll have to do it in each file that you require it in.
这样做的缺点是您必须在需要它的每个文件中执行此操作。
回答by Steve
I think you are talking about type aliasing, the way to do that in C# is using the usingkeyword.
我认为您在谈论类型别名，在 C# 中这样做的方法是使用using关键字。
e.g.
例如
using DWORD = System.Uint32
