仅显示图例 Python Matplotlib 中的某些项目
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Show only certain items in legend Python Matplotlib
提问by Funsaized
I currently am plotting a stacked bar graph of a large amount of taxonomic data, and only wish to show significant species in the legend (out of ~500 I wish to show ~25). Is there a simple way to do this? Below is the code I have:
我目前正在绘制大量分类数据的堆积条形图，并且只希望显示图例中的重要物种（我希望显示约 500 个物种中的约 25 个）。有没有一种简单的方法可以做到这一点？下面是我的代码：
labels=['0','20','40','60','80','100','120']
ax1=subj1df.plot(kind='barh', stacked=True,legend=True,cmap='Paired', grid=False)
legend(ncol=2,loc=2, bbox_to_anchor=(1.05, 1), borderaxespad=0.)
label1=['Baseline','8h','24h','48h','96h','120h']
ax1.set_yticklabels(label1, fontdict=None, minor=False)
plt.title('Subject 1 Phyla',fontweight='bold')
plt.savefig('Subject1Phyla.eps', format='eps', dpi=1000)
ax1.set_xticklabels(labels)
Edit: tried adding this to show only one legend entry, however only returns an empty legend:
编辑：尝试添加它以仅显示一个图例条目，但只返回一个空图例：
h, l = ax1.get_legend_handles_labels()
legend(l[4],h[4],ncol=2,loc=2, bbox_to_anchor=(1.05, 1), borderaxespad=0.)
采纳答案by Trond Kristiansen
I often insert an empty label for legends I don't want to show. I made an extremely simple example which I hope will help you. You will need to tweak this to your own data but the elements you need should be there.
我经常为不想显示的图例插入一个空标签。我做了一个非常简单的例子，希望对你有所帮助。您需要将其调整为您自己的数据，但您需要的元素应该在那里。
import matplotlib.pyplot as plt
import numpy as np
myY=np.random.randint(20, size=10)
myX=np.arange(0,len(myY))
selected=[5,10,15]
fig = plt.figure()
for X,Y in zip(myX,myY):
if Y in selected:
mylabel="label = %s"%(Y); mycolor='blue'
else:
mylabel=None; mycolor='red'
plt.scatter(X,Y,50, color=mycolor, label=mylabel)
plt.legend()
plt.show()
This creates the following plot:
这将创建以下图：
回答by Andrey Selivanov
For whatever reason both answers didn't work for mine situation. What worked, and actually was indicated above:
无论出于何种原因，这两个答案都不适用于我的情况。什么有效，实际上已在上面指出：
legend also takes a list of artists and a list of labels to precisely control what goes into your legend – tacaswell Jul 11 '14 at 4:46
传奇还需要艺术家列表和标签列表，以精确控制进入您的传奇的内容 – tacaswell 2014 年 7 月 11 日 4:46
import pandas as pd
import matplotlib.pyplot as plt
import pylab
pd.Series(range(10)).plot(color = 'grey')
x = list(range(10))
y = [i + 1 for i in x]
scat1 = plt.scatter(x, y)
pylab.legend([scat1],['moved points'], loc = 'upper left')
plt.show()
The result of the code:
代码的结果：
回答by Enrique Millán Valbuena
You can also use an empty string variable:
您还可以使用空字符串变量：
plt.plot(xData, yData, ..., label=str())
By passing an empty str() object, it doesn't write down anything.
通过传递一个空的 str() 对象，它不会写下任何东西。
